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4 years ago

Plsss help me I don’t understand!!

Mathematics

1 answer:

inna [77]4 years ago

6 0

Answer:

Step-by-step explanation:

in the "score" section all you do is add all them up. And because there is a negative for ALL the numbers, all you do is add a negative after you add all the SCORES

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Kevin and Anita are writing poems. kevin has no poems to start, and writes three new poems each day. Anita has four poems to sta

Aneli [31]

1 day = d

0 + 3d = 4 + 2d
3d = 4 + 2d
d = 4

It'll take 4 days

Hope this helps ^-^

7 0

3 years ago

Read 2 more answers

Complete the inequality statement.

vodomira [7]

Answer:

Step-by-step explanation:

Ggh

6 0

3 years ago

In 2002, Tim was twice as old as Sue. In 1997 the sum of their ages was 32. In what year will Sue's age be three-fourths Tim's a

xxMikexx [17]

Answer:

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = X years

In 1997, Let Sue's age = Y years

After 5 years in 2002, Tim's age = (X+ 5) years

After 5 years in 2002, Sue's age = (Y + 5) years

Now, According to question,

X + Y = 32 (sum of their ages) .......(1)

Y = 32 - X

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of Y in (2)

X + 5 = 2 (32 - X + 5)

X + 5 = 2 (37 - X )

X + 5 = 74 - 2X

3X = 69

X = 69/3 = 23

Now ∵ Y = 32 - X and X = 23

∴ Y = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after t years = (9 + t) years.

Tim's age after t years = (23 + t) years

According to question,

$(9 + t) = \frac{3}{4} \times(23 + t)$

$4 (9 + t) = 3 (23 + t)$

$36 + 4t = 69 + 3t$

$4t - 3t = 69 - 36$

$t = 33$

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

4 0

4 years ago

Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e

svet-max [94.6K]

ANSWER

$y = 2x -4$

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

$x = 5 + ln(t)$

$y = {t}^{2} + 5$

From the first equation we make t the subject to get;

$x - 5 = ln(t)$

$t = {e}^{x - 5}$

We put it into the second equation.

$y = { ({e}^{x - 5}) }^{2} + 5$

$y = { ({e}^{2(x - 5)}) } + 5$

We differentiate to get;

$\frac{dy}{dx} = 2 {e}^{2(x - 5)}$

At x=5,

$\frac{dy}{dx} = 2 {e}^{2(5 - 5)}$

$\frac{dy}{dx} = 2 {e}^{0} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5)$

$y = 2x - 10 + 6$

$y = 2x -4$

Without eliminating the parameter,

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{ 2t}{ \frac{1}{t} }$

$\frac{dy}{dx} = 2 {t}^{2}$

At x=5,

$5 = 5 + ln(t)$

$ln(t) = 0$

$t = {e}^{0} = 1$

This implies that,

$\frac{dy}{dx} = 2 {(1)}^{2} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5) =$

$y = 2x -4$

5 0

3 years ago

Question 9 ONLY!!! Please show work!!

Rufina [12.5K]

Step-by-step explanation:

Andrew paid 30% in taxes, which means he has 70% remaining

30% Cash Prize + 70% Cash Prize = 100% Cash Prize

If C = Original Cash Price

Remaining Cash = 70% x C = $28,000

C = $28,000 / 70% = 28000/0.7 = $40,000

6 0

3 years ago