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Alborosie
4 years ago
15

Daniel expanded the expression as shown. Negative 2 (Negative 8 x minus 4 y + three-fourths) = negative 10 x minus 8 y minus 1 a

nd one-fourth What errors did he make? Select three options. The first term should be positive. The second term should be positive. The last term should be Negative 1 and one-half, not Negative 1 and one-fourth. He divided Negative 8 by Negative 2 instead of multiplying Negative 8 by Negative 2. He did not simplify the expression completely.
Mathematics
2 answers:
Illusion [34]4 years ago
4 0

Answer:

Option 1,2,3

Step-by-step explanation:

got it right

malfutka [58]4 years ago
3 0

Answer:

Options A, B and C are correct.

Step-by-step explanation:

The given expression is

-2\left(-8x-4y+\dfrac{3}{4}\right)

Using distributive property, we get

-2(-8x)-2(-4y)-2\left(\dfrac{3}{4}\right)

16x+8y-\dfrac{6}{4}

16x+8y-\dfrac{3}{2}

16x+8y-1\dfrac{1}{2}

It is given that Daniel expanded the expression as

-2\left(-8x-4\dfrac{3}{4}\right)=-10x-8y-1\dfrac{1}{4}

The first term should be positive.

The second term should be positive.

The last term should be Negative 1 and one-half, not Negative 1 and one-fourth.

Therefore, options A, B and C are correct.

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A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.
olga55 [171]
We know that:

(x-a)^2+(y-b)^2=r^2

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}

and all we have to do is solve it for a, b and r.

There will be:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\


From equations (II) and (III) we have:

\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}

and from (I) and (II):

\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}

Now we can easly calculate a and b:

\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}

Finally we calculate r^2:

a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}

And the equation of the circle is:

(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}
7 0
3 years ago
Maria bought a blouse on sale for 30% off. The sale price was $28.76. What was the original price? Write an equation to model th
Snowcat [4.5K]

Answer:

The equation is <u>sale price</u>=p and the original price is $41.09.

                              .70

Step-by-step explanation:

sale price= (1-.30)p      

<u>sale price=.70</u>p

.70              .70

<u>sale price</u>=p                  

.70

<u>28.76</u>=p

.70

$41.09=p

7 0
4 years ago
Show the difference of the two sets
Rudik [331]
There is 8 fruits in set A and 7 in set B
6 0
3 years ago
Geometric Probability
KiRa [710]

Answer:

Step-by-step explanation:

1) P= Area of Circle/ Area of large rectangle

Area of the circle = pi·r² = pi·2²=4 pi ft.²

Area of large rectangle=  l·w -12·10 =120 ft.²

P = 4pi/120 rewrite 120 as 4·30

P= 4 pi/4*30 = pi/30 = 3.14/40 ≈ .1047 ≈10% (because .1047·100 =10.47≅10)

2) P = Area of smaller rectangle/ Area of large rectangle

Area of smaller rectangle = l·w = 2·4 =8 ft.²

Area of large rectangle=l·w = 12·10=120 ft²

P= 8/120 ≅ .0666≅ 7% (because .0666·100 =6.66≅7)

3) P= Not the circle or smaller rectangle/ Area of large rectangle

Not the circle or smaller rectangle area

= Area of large rectangle - Area of circle -Area of smaller rectangle

= 120 -4·pi -8 = 120 - (4· 3.14) -8 = 99.4362939 ft²

Area of large rectangle = l·w = 12·10 =120 ft²

P = 99.4362939 /120 ≅ .8286 ≅83% (because .8286·100 =82.86≅83)

7 0
3 years ago
The polygons in each pair are similar. Find the missing side length / first one has 4 &amp;x and second one has 12&amp;18
sergiy2304 [10]

Answer:

x = 6

Step-by-step explanation:

To find the missing side, write a proportion using side lengths from each similar shape. A proportion is an equation that sets equal two ratios.

\frac{4}{12}=\frac{x}{18}

Find x by cross multiplying numerator and denominator of each fraction.

4(18) = 12x

72 = 12x

6 = x

4 0
3 years ago
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