You can solve using substitution for system of equations.
So you have y = 6x and y = x^2 + 5
But it is also true that y = y since they are the same variable.
That means both y value equations are equal too:
y = 6x = y = x^2 + 5 So 6x = x^2 +5
Solve for x. x^2 - 6x + 5 = 0 Factor to (x-1)(x-5) = 0 x-1 = 0, x = 1 x-5 = 0, x = 5 So the two x-coordinate values will be (1,y value) and (5,y value)
Now to find y we use the original equations and we plug in the x values we found.
y = 6(1) = 6 y = (1)^2 + 5 = 6 So when x = 1, y = 6, the coordinate is (1,6)
y = 6(5) = 30 y = (5)^2 + 5 = 30 When x = 5, y = 30 The coordinate is (5,30)
