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2 years ago

Please help me someone

Mathematics

1 answer:

Aneli [31]2 years ago

7 0

There is a formula for the area of a parallelogram which is bxh
(base x height)

Remember the height is always straight so do not use the 12 value.

21x9=189

Hope this helped!

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4+5+8/2x9=????????????

Zolol [24]

45. Using order of operations.

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3 years ago

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Johannes want to earn at least $350 per week. His work week is 40 hrs, what is the minimum hourly wage he must make?

pentagon [3]

Answer: minimum hourly wage is $8.75

Step-by-step explanation:

To get the minimum hourly wage, we divide $350 by 40hrs

= $350 ÷ 40

= $8.75

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What is a scale factor?

Blababa [14]

Answer:

Here is some helpful information from my mini lessons.

Step-by-step explanation:

If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles shown are similar, compare their corresponding sides. Here you'll learn that the ratio of the perimeters of similar figures is equal to their scale factor and that the ratio of their areas is equal to the square of their scale factor. If two polygons are similar, then the ratio of the lengths of any two corresponding sides is called the scale factor. This means that the ratio of all parts of a polygon is the same as the ratio of the sides.

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2 years ago

A school P is 16km due west of a school Q. what is the bearing of Q from P

Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find the bearing of Q from P

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of Q $P------------------>Q$

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of School Q from P is 16Km due east of school P

7 0

3 years ago

A car advertisement claims that a certain car can accelerate from rest to 70 km/hr in 7 seconds find the car acceleration

iVinArrow [24]

Answer:

acceleration $\approx 2.78\,\,\frac{m}{s^2}$

Step-by-step explanation:

The acceleration is the change in velocity per unit of time.

Therefore to have this rate in appropriate units that can combine, we re-write the change from 0 to 70 km/h in meters per second using:

$70 \frac{km}{h} = \frac{70000}{3600} \frac{m}{s}$

so in this case the acceleration becomes:

$accel=\frac{change\,\,vel}{change\,\,time} =\frac{70000m}{3600\,*7\,s^2} \approx 2.78\,\,\frac{m}{s^2}$

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2 years ago