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3 years ago

14

The money used in jordan is called the dinar. The exchange rate is $3 to 2 dinars. How many dollars you would receiveif you exch

ange 22 dinars

1 answer:

Tema [17]3 years ago

5 0

$3---2dinars
$x---22dinars
cross multipication
so 22 ×2 then ÷3

you would recieve about 14.6 dollars or like 15 dollars

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at a small school, one male and one female are selected to represent the student body at the PTSCA meetings. if there are 41 mal

I am Lyosha [343]

It is given that there are 41 males and 48 females in the small school.

So, the number of ways a male student can be chosen from 41 males is $^{41}C_1$

Likewise, the number of ways a female student can be chosen from 48 females is $^{48}C_1$ .

Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:

$^{41}C_1\times ^{48}C_1=1968$

7 0

3 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

6 0

2 years ago

Please help i put a picture on top

jolli1 [7]

Answer:

1/8÷7

Step-by-step explanation:

I think

3 0

2 years ago

How fast does a ferrari go?

Usimov [2.4K]

Depends what Ferrari car it is.

6 0

3 years ago

Read 2 more answers

Madison makes 7 out of 12 free-throws. If she continues at the same rate, how many will she make if she shoots 156 free-throw

Alexeev081 [22]

Answer:

what is your answer choice sweetie

Step-by-step explanation:

5 0

2 years ago