Answer:
a is the right answer atleast that's what I think
X would be 84 degrees, since its corresponding angle would be worth 84.
Hope this helped!
So basically we can simplify the fraction by finding the gcf which is the greatest common factor so 14/12 both have 2 in common we simplify that by dividing by 2 so 14÷2 is 7/6 is the fraction on the left hand side and d/48 is the fraction on the right hand side so to solve for d we have to divide 336/6 whixh equals 56 as tour answer. Hoped this helped!!
Two similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line are;
- 1. Arcs are drawn to cross the given line twice on either side relative to the point
- 2. The perpendicular line is drawn using a straight edge by connecting the small arcs formed using the arcs from step 1, to the point on the line or off the line
Description:
1. One of the first steps is to place the compass on the point and from
point, draw arcs to intersect or cross the given line at two points.
2. The compass is placed at each of the intersection point in step 1 and
(opened a little wider when constructing from a point on the line) arcs are
drawn on one (the other side of the point off the line) side of the line with
the same opening (radius) of the compass to intersect each other.
3. From the point of intersection of the arcs in step 2, a line is drawn with a
straight edge passing through the given point.
Learn more about perpendicular lines here:
brainly.com/question/11505244
Answer:
The measure of ∠EFG is 52°
Step-by-step explanation:
Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.
In ΔJFG,
By angle sum property of triangle, which states that sum of all angles of triangle is 180°
m∠FJG+m∠JGF+m∠JFG=180°
⇒ 39°+13°+m∠JFG=180°
⇒ m∠JFG=180°-39°-13°=128°
As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair
⇒ m∠JFG+m∠EFG=180°
⇒ 128°+m∠EFG=180°
⇒ m∠EFG=52°
The measure of ∠EFG is 52°
