Ask question

Ask question

All categories

2 years ago

8

Delta math help me pleaseeeeeee

2 answers:

lozanna [386]2 years ago

7 0

The answer is 5,12,14

Citrus2011 [14]2 years ago

5 0

The correct answer is 5,12,14

You might be interested in

What is the answer to 5x6+6x3+4x9

juin [17]

Use order of operations
P
E
M
D
A
S

So multiply 5x6 to get 30
Then times 6x3 to get 18
Next times 4x9 to get 36

Add 30, 18, and 36 together to get

84

8 0

3 years ago

Read 2 more answers

A, B and C are collinear points. B is between A and C. AB=12 BC=18 AC=3x Find X.

SCORPION-xisa [38]

Answer:

$x =10$

Step-by-step explanation:

Given

$AB = 12$

$BC = 18$

$AC = 3x$

Required

Solve for x

Since B is in between both points, then:

$AC = AB + BC$

This gives

$3x = 12 + 18$

$3x = 30$

Divide by 3

$x =10$

3 0

3 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago

A sail boat has a sail in the shape of an isosceles triangle. the base of the triangle is 16 feet in length. the height of the s

lapo4ka [179]

Answer:

160 feet^2

Step-by-step explanation:

base x high x 1/2

hope i'm right

3 0

2 years ago

Read 2 more answers

Solve the system of equations.<br><br><br> <br><br> −5y−10x=45<br> −3y+10x=−5<br>

Fynjy0 [20]

(-2,-5)
The first goal with equations like these is to get one of the variables to go away. You can do that by adding/subtracting one equation from the other. Then you solve for the one variable. Then you plug that answer into one of the original equations and solve.

4 0

3 years ago

Read 2 more answers