Answer:
The image is (-18,0)
Step-by-step explanation:
Here, we want to find the image of the given point after dilation by the given scale factor
Mathematically, given a point with the pre-image (x,y) going under the dilation of scale factor k, centered at the origin, the coordinates of the image will be;
(kx , ky)
Applying this in the given scenario, we have
(2(-9) , 2(0))
= (-18,0)
Answer: Wait a minute, Is the answer is 144 cubic centimetres?
Step-by-step explanation: So this is the given formula volumebox = width x length x height. Measure any two sides (length, width or height) of an object or surface in order to get a two-dimensional measurement, then multiply the width, length, and the height: 12*6*2=144 cm^3.
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
F: R → R is given by, f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1
So, f(1.2) = f(1.9), but 1.2 ≠ 1.9
f is not one-one
Now, consider 0.7 ε R
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ε R such that f(x) = 0.7
So, f is not onto
Hence, the greatest integer function is neither one-one nor onto.
The answer was quite complicated but I hope it will help you.
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