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Lisa [10]
3 years ago
11

Among all rectangles that have a perimeter of 134, find the dimensions of the one whose area is largest. write your answers as f

ractions reduced to lowest terms.
Mathematics
1 answer:
mestny [16]3 years ago
8 0
The answer to this question would be: L= 33.5, W=33.5

In this question, the rectangle has a perimeter of 134. From this number, you can get this equation:

perimeter=134
2(L+W)= 134
L+W=67
L= 67-W

Using the formula for dimension you can get this equation:
dimension= L * W
dimension= (67-W)W= 67W- W^2

The maximum dimension should be differentiation of the equation which will look like:
67 -2w= 0
2w= 67
w= 33.5
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which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = x2 – 10x 2? righ
irina1246 [14]

Answer:

5 units to the right and 23 units down

Step-by-step explanation:

we have

f(x)=x^{2}

This is a vertical parabola open upward with vertex at point (0,0)

g(x)=x^{2} -10x+2

Step 1

Convert the function g(x) into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

g(x)-2=x^{2} -10x

Complete the square. Remember to balance the equation by adding the same constants to each side

g(x)-2+25=x^{2} -10x+25

g(x)+23=x^{2} -10x+25

Rewrite as perfect squares

g(x)+23=(x-5)^{2}

g(x)=(x-5)^{2}-23

The function g(x) is a vertical parabola with the vertex at point (5,-23)

Step 2

Find the rule of the translation

(0,0)-------> (5,-23)

(x,y)-------> (x+5,y-23)

That means

The translation is 5 units to the right and 23 units down

6 0
3 years ago
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A racing car used 255 litres of fuel to complete a 340 km race.
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The answer is 151 km.
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The width of a rectangle is 4x−9.5 feet and the length is 9.5x+10 feet. Find the perimeter of the rectangle.
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Answer:

.037 feet

Step-by-step explanation:

perimeter = the sum of all four sides so

perimeter = (4x-9.5) + (9.5x + 10)  + (4x - 9.5) + (9.5x + 10)  = 27x = 1

therefore x = 1/27  = .037 feet

7 0
3 years ago
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The figure is composed of a rectangular prism and a triangular prism. Find the volume of the figure.
Darya [45]

<u>Given</u>:

The given figure is composed of a rectangular prism and a triangular prism.

The length of the rectangular prism is 30 inches.

The width of the rectangular prism is 14 inches.

The height of the rectangular prism is 14 inches.

The base of the triangle is 7 inches.

We need to determine the volume of the composite figure.

<u>Volume of the rectangular prism:</u>

The volume of the rectangular prism can be determined using the formula,

V=lwh

Substituting l = 30, w = 14 and h = 14, we get;

V=30 \times 14 \times 14

V=5880 \ in^3

Thus, the volume of the rectangular prism is 5880 cubic inches.

<u>Volume of the triangular prism:</u>

The volume of the triangular prism can be determined using the formula,

V=\frac{1}{2}bhl

where b is the base of the triangle,

h is the height of the triangle and

l is the length of the prism.

Substituting b = 7, h = 14 and l = 30, we get;

V=\frac{1}{2}(7)(14)(30)

V=1470 \ in^3

Thus, the volume of the triangular prism is 1470 cubic inches.

<u>Volume of the composite figure:</u>

The volume of the composite figure can be determined by adding the volume of the rectangular prism and the volume of the triangular prism.

Thus, we have;

Volume = 5880+1470

Volume = 7350 \ in^3

Hence, the volume of the composite figure is 7350 cubic inches.

5 0
3 years ago
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