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evablogger [386]
4 years ago
7

Determine the measure of each missing angle

Mathematics
1 answer:
Drupady [299]4 years ago
8 0

Answer:

w=y=86

Step-by-step explanation:

A triangle has a total angle of 180 degrees

w=y because the triangle is isoceles meaning that two sides are the same length (they are marked with a line through them)

180-94=86 degrees=w+y

w+y so 86/2=43 degrees

w=y=86

is that all the missing angles?

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Ranjit wants to measure the length of a table, but has no ruler or
krok68 [10]

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  108 cm

Step-by-step explanation:

6 pencil-lengths will be ...

  6 × 18 cm = 108 cm

The length of the table is 108 cm.

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4 years ago
Which of the following is an arithmetic sequence?
insens350 [35]

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3 years ago
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Q 2 PLEASE HELP ME FIGURE THIS OUT
suter [353]

Answer: IV, positive, \frac{\pi} {6}, - sec \frac{\pi} {6}, \frac{2\sqrt{3}}{3}

<u>Step-by-step explanation:</u>

a) Look at the Unit Circle to see that \frac{11\pi} {6} = 330°, which is located in Quadrant IV.

b) The coordinate (cos θ, sin θ) for \frac{11\pi} {6} is: (\frac{\sqrt{3}} {2},\frac{-1}{2})

sec = \frac{1}{cos} = \frac{2}{\sqrt{3}} which is positive

c) Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the given angle \frac{11\pi} {6} from 2π: \frac{12\pi} {6} - \frac{11\pi} {6} = \frac{\pi} {6}

d) the reference angle is below the x-axis so the given angle is equal to the negative of the reference angle: - sec \frac{\pi} {6}.

e) sec \frac{11\pi} {6} = \frac{2}{\sqrt{3}} = \frac{2}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}} = \frac{2\sqrt{3}}{3}

***************************************************************************************

Answer: \frac{18\pi}{11}, IV, \frac{4\pi} {11}

<u>Step-by-step explanation:</u>

2π is one rotation.  2π = \frac{22\pi}{11}

\frac{-26\pi}{11} + \frac{22\pi}{11} = \frac{-4\pi}{11}

\frac{-4\pi}{11} + \frac{22\pi}{11} = \frac{18\pi}{11}

Convert the radians into degrees to see which Quadrant it is in by setting up the proportion and cross multiplying:

\frac{\pi}{180}= \frac{18\pi}{11x}

π(11x) = (180)18π

x = \frac{180(18\pi}{11\pi}

x = 295°     <em>which lies in Quadrant IV</em>

Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the angle of least nonegative value\frac{18\pi} {11} from 2π: \frac{22\pi} {11} - \frac{18\pi} {11} = \frac{4\pi} {11}

***************************************************************************************

Answer: \frac{5\pi}{3}, IV, \frac{4\pi} {11}, \frac{\pi} {3}

<u>Step-by-step explanation:</u>

2π is one rotation.  2π = \frac{6\pi}{3}

\frac{-13\pi}{3} + \frac{6\pi}{3} = \frac{-7\pi}{3}

\frac{-7\pi}{3} + \frac{6\pi}{3} = \frac{-\pi}{3}

\frac{-\pi}{3} + \frac{6\pi}{3} = \frac{5\pi}{3}

This is on the Unit Circle at 300°, which is located in Quadrant IV

Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the angle of least nonegative value\frac{5\pi} {3} from 2π: \frac{6\pi} {3} - \frac{5\pi} {3} = \frac{\pi} {3}


7 0
4 years ago
As part of their business promotional package, the Milwaukee Chamber of Commerce would like an estimate of the mean cost per mon
Morgarella [4.7K]

Answer:

a) 884-2.426\frac{50}{\sqrt{40}}=864.82    

884+2.426\frac{50}{\sqrt{40}}=903.179    

So on this case the 98% confidence interval would be given by (864.82;903.179)

b) For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=884 represent the sample mean

\mu population mean (variable of interest)

s=50 represent the sample standard deviation

n=40 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,39)".And we see that t_{\alpha/2}=2.426

Now we have everything in order to replace into formula (1):

884-2.426\frac{50}{\sqrt{40}}=864.82    

884+2.426\frac{50}{\sqrt{40}}=903.179    

So on this case the 98% confidence interval would be given by (864.82;903.179)

Part b

For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

3 0
3 years ago
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