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3 years ago

Find the surface area of the composite figure shown?

Mathematics

1 answer:

GuDViN [60]3 years ago

3 0

Mmmmmmmmmmmfhchxjchxgxydychcydtdy

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Evaluate 8(7x--3) when x=9

Schach [20]

I will assume that by "Evaluate 8(7x--3) when x=9" you meant:

"Evaluate 8(7x-3) when x=9."

First, substitute 9 for x in 7x-3: 7(9)-3 = 60. Rewrite the problem as:

8(60). Multiply. Answer: 480

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3 years ago

Write down one pro and one con of employment.

lapo4ka [179]

Answer:

Pro: Monthly income to pay bills, buy food ,etc

Con: You many feel tied down, you could get abused at work (taken advantage of)

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2 years ago

Use parentheses to make 5+4×3×3

kherson [118]

The aNSWER IS 41..AM I RIGHT?

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3 years ago

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Which of the following equations defines a line that is parallel to the line y=-4/3x-4 and passes through the point (3,-1)

ValentinkaMS [17]

Answer:

Step-by-step explanation:

given that your slop is -4/3, plug the (x,y) point in to the equation of y = -4x/3 +b

-1 = -4 + b , b = 3

y = -4x/3 + 3

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3 years ago

Read 2 more answers

Show Work Please Thank You

Misha Larkins [42]

Answer:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

Step-by-step explanation:

We are given the trigonometric equation of:

$\displaystyle{\sin 4x = \dfrac{\sqrt{3}}{2}}$

Let u = 4x then:

$\displaystyle{\sin u = \dfrac{\sqrt{3}}{2}}\\\\\displaystyle{\arcsin (\sin u) = \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}\\\\\displaystyle{u= \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}$

Find a measurement that makes sin(u) = √3/2 true within [0, π) which are u = 60° (π/3) and u = 120° (2π/3).

$\displaystyle{u = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

Convert u-term back to 4x:

$\displaystyle{4x = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

Divide both sides by 4:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

The interval is given to be 0 ≤ 4x < π therefore the new interval is 0 ≤ x < π/4 and these solutions are valid since they are still in the interval.

Therefore:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

8 0

1 year ago