Answer:
B its B
Step-by-step explanation:
It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
15 dollars
Step-by-step explanation:
We can write a ratio to solve
6 cones 9 cones
------------ = --------------
10 dollars x dollars
Using cross products
6*x = 10 *9
6x = 90
Divide each side by 6
6x/6 = 90/6
x = 15
Answer:
see explanation
Step-by-step explanation:
Using the identity
tan²x = sec²x - 1
Consider left side
sec²x + tan²x
= sec²x + sec²x - 1
= 2sec²x - 1
= right side , thus verified
<span>Break down every term into prime factors. ...Look for factors that appear in every single term to determine the GCF. ...Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...<span>Multiply out to simplify each term. </span></span>
