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Kruka [31]
3 years ago
15

An object has a mass of 4 grams and a volume of 2 cm3 what is the density of the object ​

Chemistry
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

D = 2 g/cm³

Explanation:

Density = mass over volume

D = m/v

Step 1: Define

m = 4 grams

v = 2 cm³

Step 2: Substitute and Evaluate

D = 4 g/2 cm³

D = 2 g/cm³

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In response to Boyle’s Law, the pressure of a gas increases as the volume decreases because
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Answer:

the gas particles strike the walls of the container more often

Explanation:

Following Boyle's law, if the amount of gas and the temperature remain constant, the product of the pressure for the volume remains constant, but when altering any of these conditions this value changes and is expressed through the equation:

<em>                                                       </em>P_{1} V_{1}  = P_{2}V_{2}<em></em>

So, when the volume decreases, the distance that the particles have to travel is smaller and therefore more collisions between particles and between the walls occur per unit of time, that is, the system pressure increases.

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Water can act as both an acid and a base in an ionization reaction to form (H) and OH ions.
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Convert to moles: show work
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Which of the following would diffuse through a cell membrane the most easily?
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How many grams of Fe will be produced if 705.0g of H20 are produced?
fredd [130]
<h3>Answer:</h3>

2265 g Fe₃O₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O

[Given] 705.0 g H₂O

<u>Step 2: Identify Conversions</u>

[RxN] 4 mol H₂O → 1 mol Fe₃O₄

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe - 55.85 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol

<u>Step 3: Convert</u>

  1. Set up stoich:                              \displaystyle 705.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{1 \ mol \ Fe_3O_4}{4 \ mol \ H_2O})(\frac{231.55 \ g \ Fe_3O_4}{1 \ mol \ Fe_3O_4})
  2. Multiply/Divide/Cancel units:                                                                           \displaystyle 2264.74 \ g \ Fe_3O_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄

5 0
3 years ago
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