An Arrhenius base is a substance that are being dissolves in water dissociate and gives Hydroxide ions. (OH⁻)
Find the [OH-] in the solution. The pH is 9.5, so the pOH is 14 - 9.5 = 4.5.
[OH-] = 10^-4.5 M
Now use the dilution equation to find the new [OH-] after the volume is reduced from 150 mL to 50 mL:
M1V1 = M2V2
M1 = 10^-4.5 M
V1 = 150 mL
M2 = ?
V2 = 50 mL
(10^-4.5)(150) = M2(50)
M2 = 9.5 x 10^-5 M ≈ 1 • 10^-4 (We can only use one sig fig, because the pH was given to one decimal place.)
Now use this [OH-] to find pOH:
pOH = -log(1 x 10^-4) = 4.0
14 - pOH = pH, so the expected pH for the new solution is 10.
The specific heat of the iron can is determined as 0.449 J/g⁰C.
<h3>Specific heat of the iron can</h3>
The specific heat of the iron can is calculated as follows;
Q = mcΔθ
c = Q/mΔθ
where;
- Q is quantity of heat
- Δθ is change in temperature
- m is mass
c = 256/(50 x 11.4)
c = 0.449 J/g⁰C
Thus, the specific heat of the iron can is determined as 0.449 J/g⁰C.
Learn more about specific heat here: brainly.com/question/16559442
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The answer to your question is 4. I and F.
