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drek231 [11]
3 years ago
9

Water can act as both an acid and a base in an ionization reaction to form (H) and OH ions.

Chemistry
2 answers:
mart [117]3 years ago
6 0
Amphoterism. amphoteric substance is a substance/compound that can act as both acid and base
matrenka [14]3 years ago
4 0
Sorry I need points :)
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The rate of formation of C in the reaction 2 A + B →2 C + 3 D is 2.7 mol dm−3 s −1 . State the reaction rate, and the rates of f
Zielflug [23.3K]

Answer:

Rate of reaction =1.35mol.dm^{-3}.s^{-1}

Rate of consumption of A = 2.7mol.dm^{-3}.s^{-1}

Rate of consumption of B = 1.35mol.dm^{-3}.s^{-1}

Rate of formation of D = 4.15mol.dm^{-3}.s^{-1}

Explanation:

According to laws of mass action for the given reaction,

Rate= -\frac{1}{2}\frac{\Delta [A]}{\Delta t}=-\frac{\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}=\frac{1}{3}\frac{\Delta [D]}{\Delta t}

where, -\frac{\Delta [A]}{\Delta t} is rate of consumption of A, -\frac{\Delta [B]}{\Delta t} is rate of consumption of B, \frac{\Delta [C]}{\Delta t} is rate of formation of C and \frac{\Delta [D]}{\Delta t} is rate of formation of D

Here \frac{\Delta [C]}{\Delta t}=2.7mol.dm^{-3}.s^{-1}

So, Rate of reaction = (\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}

Rate of formation of D = (\frac{3}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{3}{2}\times 2.7mol.dm^{-3}.s^{-1})=4.15mol.dm^{-3}.s^{-1}

Rate of consumption of A = (\frac{2}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{2}{2}\times 2.7mol.dm^{-3}.s^{-1})=2.7mol.dm^{-3}.s^{-1}

Rate of consumption of B = (\frac{1}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}

3 0
3 years ago
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