Question

Plz see attachment below

Answer 1

Answer:

Step-by-step explanation:

Table I

Given function is,

f(x) = $b^x$

From the table attached,

For x = 0.827, value of function f(0.827) = 5,

f(0.827) = $b^{0.827}$

Therefore, $b^{0.827}=5$

$\text{log}(b^{0.827})=\text{log}(5)$

0.827[log(b)] = log(5)

log(b) = 0.8452

b = $10^{0.8452}$

b = 7

Therefore, function 'f' will be,

f(x) = $7^x$

For f(x) = 9,

9 = $7^x$

log(9) = log($7^x$)

log(9) = x[log(7)]

x = 1.129

Table II

Given function is g(x) = $\text{log}_b(x)$

From the given table,

For x = 7, g(x) = 1

1 = $\text{log}_b(7)$

$b^1=7$

b = 7

Therefore, the function 'g' will be,

g(x) = $\text{log}_7(x)$

For g(x) = 1.318

1.318 = $\text{log}_7(x)$

$x=7^{1.318}$

$x=12.9968$

$x=13.997$