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4 years ago

The development of the cell theory was mostly directly related to the

Physics

1 answer:

Mazyrski [523]4 years ago

8 0

Answer:

Development of the gene chromosome theory

Explanation:

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a 2.00 kg friction-less block is attached to an ideal spring with force constant 315 N/m.Initially, the spring is neither stretc

Setler [38]

Answer

given,

mass of block, m = 2 Kg

spring constant, k = 315 N/m

speed of the block, v = 12 m/s

a) Amplitude of the motion

$A = v \sqrt{\dfrac{k}{m}}$

$A =\dfrac{12}{\sqrt{\dfrac{315}{2}}}$

A = 0.956 m

b) maximum acceleration of the block

$a_{max}= A \dfrac{k}{m}$

$a_{max}= 0.956\times \dfrac{315}{2}$

$a_{max}= 150.57\ m/s^2$

c) maximum Force

$F_{max} = m a_{max}$

$F_{max} = 2\times 150.57$

$F_{max} = 301.14\ N$

5 0

3 years ago

Name two things radio waves have in common with visible light

kondaur [170]

Radio waves and visible light, as we perceive it, are both part of the EM spectrum. The only difference between them in terms of our perception is that we don't have receptors to 'see' radio waves. That's where radio receivers come into the picture*, to convert radio waves into sound impulses that we can hear.

8 0

3 years ago

A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 4500 N/C and is directed in

Anton [14]

Answer with Explanation:

We are given that

$E=4500 N/C$

$q=-5.5\times 10^{-9} C$

a.x=-0.2 m

$E'=\frac{Kq}{r^2}=\frac{9\times 10^9\times 5.5\times 10^{-9}}{(0.2)^2}=1237.5 N$

Where $k=9\times 10^9$

Net electric field=E+E'=4500+1237.5=5737.5 N/C

b.x=0.20 m

Net electric field=E-E'=4500-1237.5=3262.5 N/C

c.y=0.20 m

E=1237.5 N/C

Net electric field= $\sqrt{E^2+E'^2}=\sqrt{(4500)^2+(1237.5)^2}=4667.05 N/C$

7 0

3 years ago

Define specific heat capacity

sleet_krkn [62]

Answer:you can just look this up yknow?

Explanation:

7 0

3 years ago

Read 2 more answers

What was his average swimming speed during the second half of the race if he tied the record, which was at an average speed of 2

Nimfa-mama [501]

<span>I believe this question has additional detail which stated that during the 1st half, his speed was 2.01 m/s. From this we can calculate his speed during the second half, v2, using the formula:</span>

v_ave = (v1 + v2) / 2

2.05 m/s = (2.01 m/s + v2) / 2

4 0

3 years ago