Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
Here, 3x + 2y = 12
2x + 2y = 10
Subtract 2nd from 1st equation,
x = 2
Now, substitute in 2nd,
2(2) + 2y = 10
2y = 10 - 4
y = 6/2
y = 3
In short, Your Answer would be: (2, 3)
Hope this helps!
Answer:
2/1 or 2
Step-by-step explanation:
the way to find the slope is rise over run, if you count the units you see that for every time it rises 2 it runs 1, then divide.
Answer:
-4.5 is less than 3
-12/5 is less than 2
-3, -1.5, -1, 0, 2, 2.75, 5, 5.2
-3/2 = -1.5
11/4 = 2.75