Ask question

Ask question

All categories

schepotkina [342]

3 years ago

15

Joanne bought a box of pens for $3.75. There are 100 pens in a box. The pens individually cost 7 cents. How much money did she s

ave? A. $3.25 B. $0.38 C. $7.00 D. $10.75

2 answers:

lesantik [10]3 years ago

7 0

Answer:

The answer is C) $7.00

PtichkaEL [24]3 years ago

4 0

Answer: A $3.25

Step-by-step explanation:

Each pen cost 7pm. So 100 pens would have cost 7p x 100 = $7

She bought a box of hundred for $3.75

He actually saved:

7 - 3.75 = 3.25

You might be interested in

Five-sixths of the distance from 1 to −13

Finger [1]

The distance of 1 to -13 is 14.

Five sixths of this is (.8333*14), which equals 11.6667.

8 0

3 years ago

a rectangular park has an area of 2/3 square miles the length of the park is 2 and 2/3 the width of the park what is the Widht o

r-ruslan [8.4K]

1.33333333333 thats the answer

5 0

3 years ago

Select the postulate or theorem that you can use to conclude that the triangles are similar.

insens350 [35]

Answer: SAS similarity postulate

Step-by-step explanation:

According to SAS postulate of similarity, two triangles are called similar if two sides in one triangle are in the same proportion to the corresponding sides in the other, and the included angle are congruent.

In triangles, QNR and MNP,

$\frac{QN}{MN} = \frac{QM+MN}{MN} = \frac{10+8}{8} = \frac{18}{8} = \frac{9}{4}$

$\frac{NR}{NP} = \frac{NP+NR}{NP} = \frac{10+8}{8} = \frac{18}{8} = \frac{9}{4}$

$\implies \frac{QN}{MN} = \frac{NR}{NP}$

Also,

$\angle QNR\cong \angle MNP$ (Reflexive)

Thus, By SAS similarity postulate,

$\triangle QNR\sim\triangle MNP$

⇒ Option first is correct.

8 0

3 years ago

Whats the error?katie divided 4.25 by 0.25 and a got a quotient of 0.17.

m_a_m_a [10]

The answer is 17. The decimal point needed to be moved by 2 places to the right since the divisor is a decimal.

6 0

4 years ago

30 points I'm struggling Find the equations of each line and show all of your work. (1, 5) (2, 6) (1, 1) (3, -8) (2, -3) (5, -2)

Free_Kalibri [48]

Answer:

1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b

5=1(1)+b 4=b

y=x+4

2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b

1=-9/2(1)+b b=11/2

y=-9/x+11/2

3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b

-3=1/3(2)+b -3=2/3+b

-3-2/3=b

b=-11/3

y=1/3x-11/3

4.(2,5)and (4,3) m=-1 y=-1x+b

5=-1(2)+b 5=-2+b

5+2=b

b=7

y=-1x+7

6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b

-5=1(-3)+b -5=-3+b

-5+3=b

-2=b

y=1x-2

Step-by-step explanation:

7 0

3 years ago