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Snezhnost [94]
3 years ago
12

What do I do I thought it was a but my teacher said it was wrong so what do I do ?

Mathematics
2 answers:
mylen [45]3 years ago
4 0

Do length × width × hight

you just get 840 cf

faltersainse [42]3 years ago
4 0
The answer is c
V=1/2a•c•h
V=0.5(7)•10•12
V=3.5(10)•12
V=30(12)
V=420
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What is the nth term of 12 10 8 6 4 ?
tino4ka555 [31]

Answer:

-4

Step-by-step explanation:

The difference from each number is 2 so u keep subtracting 2 from each term until u get to the nth term. For ex: 12-2=10, 10-2=8, 8-2=6...

7 0
3 years ago
Penelope determined the solutions of the quadratic function by completing the square. F(x) = 4x2 8x 1 –1 = 4x2 8x –1 = 4(x2 2x)
Ymorist [56]

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

<h3>What is quadratic equation ?</h3>

Any equation of the form ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called quadratic equation .

Given work of Penelope is

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+1=4\left(x^{2}+2 x+1\right) \\&0=4(x+2)^{2} \\&0=(x+2)^{2} \\&0=x+2 \\&-2=x\end{aligned}$$

Now we can see that Penelope determined the solutions of the quadratic function by completing the square. so he must have been done as following

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+4=4\left(x^{2}+2 x+1\right) \\&3=4(x+2)^{2} \\&\frac{3}{4} =x+2)^{2} \\&\frac{\pm\sqrt3}{2} =x+2 \\&\frac{-2\pm\sqrt3}{2} =x\end{aligned}$$

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

To learn more about quadratic equations visit : brainly.com/question/1214333

8 0
2 years ago
the first term of an arithmetic sequence is 2 and the sum of the first 15 terms is 292.5. Find the common difference
adelina 88 [10]

Given:

First term of an arithmetic sequence is 2.

Sum of first 15 terms = 292.5

To find:

The common difference.

Solution:

We have,

First term: a=2

Sum of first 15 terms: S_{15}=292.5

The formula of sum of first n terms of an AP is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Where, a is first term and d is common difference.

Putting S_{15}=292.5, n=15 and a=2 in the above formula, we get

292.5=\dfrac{15}{2}[2(2)+(15-1)d]

292.5=\dfrac{15}{2}[4+14d]

292.5=15[2+7d]

Divide both sides by 15.

\dfrac{292.5}{15}=2+7d

19.5=2+7d

19.5-2=7d

17.5=7d

Dividing both sides by 7, we get

\dfrac{17.5}{7}=d

2.5=d

Therefore, the common difference is 2.5.

8 0
3 years ago
Expand the following:
liraira [26]

Answer:

8x-16y

Step-by-step explanation:

  • b.6a/6+18b/6-12c/6
6 0
3 years ago
Read 2 more answers
Multiple Choice Question
yan [13]
I believe the right answer is B!
7 0
3 years ago
Read 2 more answers
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