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3 years ago

Estimate 307‾‾‾‾√ between two consecutive whole numbers. Enter the numbers in the boxes below.

Mathematics

1 answer:

creativ13 [48]3 years ago

8 0

Answer:

17, 18

Step-by-step explanation:

closest perfect square that is lower than 307 is 289

closest perfect square that is greater than 307 is 324

$\sqrt{289} < \sqrt{307} < \sqrt{324}$

$17$

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Two solutions exist for the system of equations in the graph.

Step-by-step explanation:

Solutions are when the two graphs intersect.

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2 years ago

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4 years ago

Matt and Ash are selling fruit for a school fundraiser. Customers can buy small boxes of fruit or

aliina [53]

Answer: The cost of a small box is $4. The cost of a large box is $7.

Step-by-step explanation:

Let s = cost of a small box and L = cost of a large box

3s + 5L = 47

11s + 10L = 114

Multiply the top equation by -2 to combine with the second equation

-6s - 10L = -94

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L cancels out, now solve for s

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Now, plug the value of s back into an equation to find the value of L

3(4) + 5L =47

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5 0

3 years ago

A fair ordinary dice is rolled once. What is the probability of rolling a 3 or 4?

Ahat [919]

Answer:

A dice is six sided which would mean that the probablilty would be out of 6, since you have 2 options it leaves you with 2/6.

Step-by-step explanation:

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4 years ago

Three identical fair coins are thrown simultaneously until all three show the same face. What is the probability that they are t

mixer [17]

Answer:

The probability that the coins are thrown more than three times to show the same face is 0.3164.

Step-by-step explanation:

The problem is related to Geometric distribution.

The Geometric distribution defines the probability distribution of X failures before the first success.

The probability distribution function is:

$P(X=k)=(1-p)^{k}p;\ k = 0, 1, 2, ...$

First compute the probability that in the $i^{th}$ throw all the three coins will show the same face.

P (All the 3 coins shows the same face) = P (All the three coins shows Heads) + P (All the three coins shows Tails)

$=(\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} )+(\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} )\\=\frac{1}{8}+\frac{1}{8}\\ =\frac{2}{8} \\=\frac{1}{4}$

Now compute the probability that it takes more than 3 throws for the coins to show the same face.

P (X > 3) = 1 - P (X ≤ 3)

$=1-[P(X=1)+P(X=2)+P(X=3)]\\=1-[[(1-\frac{1}{4} )^{0}\times\frac{1}{4}]+[(1-\frac{1}{4} )^{1}\times\frac{1}{4}]+ [(1-\frac{1}{4} )^{2}\times\frac{1}{4}]+[(1-\frac{1}{4} )^{3}\times\frac{1}{4}]]\\=1-[0.2500+0.1875+0.1406+0.1055]\\=1-0.6836\\=0.3164$

Thus, the probability that it takes more than 3 throws for the coins to show the same face is 0.3164.

8 0

3 years ago