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lorasvet [3.4K]
3 years ago
12

5. – 3(1 + 6r) = 14 - 7​

Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

r= -1.8

Step-by-step explanation:

Distribute

-3-18r=14-7

Combine like terms

-3-18r=7

add 3 to both sides

-18r=10

divide by -18

r=-1.8

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A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be
irga5000 [103]

Answer:

The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let C = (h,k) the coordinates of the center of the circle, which must be transformed into C'=(h', k') by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

(x-h)^{2}+(y-k)^{2} = r^{2}

Where r is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

C''(x,y) = C(x, y) + U(x,y) (Eq. 1)

Where U(x,y) is the translation vector, dimensionless.

If we know that C(x, y) = (h,k) and U(x,y) = (4, 0), then:

C''(x,y) = (h,k)+(4,0)

C''(x,y) =(h+4,k)

2) <em>Reflection over the x-axis</em>:

C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)] (Eq. 2)

Where O(x,y) is the reflection point, dimensionless.

If we know that O(x,y) = (h+4,0) and C''(x,y) =(h+4,k), the new point is:

C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]

C'(x,y) = (h+4, 0)-(0,k)

C'(x,y) = (h+4, -k)

And thus, h' = h+4 and k' = -k. The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

<em />

4 0
3 years ago
Which is true about the polynomial –8m3 + 11m?
Mumz [18]

Answer:

b) It is a binomial with a degree of 3.

Step-by-step explanation:

We need to find about which is true about the polynomial –8m3 + 11m from the given choices.

There are two terms so it is binomial.

Highest exponent on variable m is 3 so degree is 3.

Correct matching choice is "It is a binomial with a degree of 3."

Hence final answer is choice "b) It is a binomial with a degree of 3."


4 0
2 years ago
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8 0
3 years ago
What is the value of x?
Aleksandr [31]

Answer:

x = 20

Step-by-step explanation:

these are vertical angles and vertical angles are congruent

3x+50 = 6x-10

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x = 20

6 0
3 years ago
A car dealer acquires a used car for $14,000, with terms FOB shipping point. compute total inventory costs assigned to the used
Artyom0805 [142]

Given:

A car dealer acquires a used car for $14,000, with terms FOB shipping point.

Transportation cost = $100

Shipping insurance = $120

Car import duties = $970

To find:

The total inventory costs assigned to the used car.

Solution:

We know that,

Inventory costs = Value of used car + Transportation cost + Shipping insurance + Car import duties

Inventory costs = $14,000 + $100 + $120 + $970

Inventory costs = $15,190

Therefore, total inventory costs assigned to the used car is $15,190.

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