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amid [387]
3 years ago
5

HELP HELP HELP DUE IN 12 mins

Mathematics
1 answer:
Ghella [55]3 years ago
5 0

Answer:

We can't seee the whole problem...

Step-by-step explanation:

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PLEASE HELP I NEED ANSWER
Usimov [2.4K]
(6x-1)+20+(x+14)=180
6x-1+20+x+14=180
6x+x+20+14-1=180
7x+33=180
-33 -33
7x=147
7/7x=147/7
x=21

Measure of angle A=:
(6x-1)
6x-1
6(21)-1
126-1
125
Measure of angle A is 125°

Measure of angle C=
(x+14)
x+14
21+14
35
Measure of angle C is 35°
4 0
3 years ago
How do u solve y pluse 4 pluse 3(y pluse 2)
lesya [120]
Y + 4 + 3(y+2)    first distribute the 3
y + 4 + 3y + 6     then add like terms
4y + 10

therefore your answer should be  4y + 10
3 0
4 years ago
Read 2 more answers
Mario is constructing a frame for a 10 in .by 8 in. photo. He wants the frame to be the same width all the way around and the to
alexgriva [62]
(10+2x)(8+2x) = 120
4x^2 + 36x + 80 = 120
x^2 + 9x + 20 = 30

x^2 + 9x - 10 = 0

(x+10)(x-1) = 0

x = 1 inch dimension
8 0
4 years ago
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Solve: x/3+1/4 =1/3 . Explain your work.
mojhsa [17]

Steps to solve:

x/3 + 1/4 = 1/3

~Subtract 1/4 to both sides

x/3 = 1/12

~Multiply 3 to both sides

x = 1/4

Best of Luck!

5 0
3 years ago
The dimensions of the base of Box 1 are x by 3x. The base area of Box 1 is: 3x 3x2 3x3 4x
Lunna [17]
<h3>The base area of box 1 is 3x^2\ square\ units</h3>

<em><u>Solution:</u></em>

Given that,

The dimensions of the base of Box 1 are x by 3x

Length = x

Width = 3x

To find: base area of box 1

<em><u>The base area is given as:</u></em>

base\ area = length \times width\\\\base\ area = x \times 3x\\\\base\ area = 3x^2

Thus base area of box 1 is 3x^2\ square\ units

4 0
4 years ago
Read 2 more answers
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