Solve pls brainliest

Hello <3 ~ ! can you help me please <3 ? Thank you)

Neko [114]

So, for number two, you fill in the numbers that theyve given you
x. y
1. 5
2. 3
3. 2
4. 1
5. 0
then you just draw the graph and draw arrows to the integers

8 0

3 years ago

Aisha and jordan start by making a floor plan for their treehouWhich revision of these two sentences best shows that the coach b

irina1246 [14]

Answer: Statements 1 and 2 shows that the coach blowing the whistle happened first.

Step-by-step explanation: The coach blowing the whistle as the first event can be seen only from statements 1 and 2 only.

From statement 1, "the referee blew the whistle" was followed by "the team ran onto the field."

From statement 2, "before the team ran onto the field" shows clearly that one event took place "BEFORE" the one being reported and the one that occurred before this one was "the referee blew the whistle."

Statement 3 which is "the referee blew the whistle, BUT..." indicates that the whistle was meant to prevent the team from from running onto the field. So if the referee blew the whistle, but the team ran onto the field, it means the whistle blowing was not supposed to make them run onto the field.

Statement 4, which states that "the referee blew the whistle BECAUSE the team ran onto the field" indicates that, the reason for blowing the whistle was because the team ran onto the field which clearly shows that the team ran onto the field first before the referee blew the whistle.

Statement 5, "WHILE the team ran onto the field..." clearly shows that both events took place at the same moment, and so the referee blowing the whistle could not have occurred first.

8 0

3 years ago

HURRY STRANGERS PLEASE I REALLY NEED THIS!!! A paper manufacturer is evaluating their packing procedures. Currently, they packag

drek231 [11]

Answer:

Step-by-step explanation:

Base on my own understanding what should be done is that three stacks will not work, because it wont be a symmetric arrangement and also one will be left out. So, two stacks of five each would be better and easy to carry. But the stacks should be arranged in such a manner that the lengths will be parallel to each other and not in-line which would increase the length making it comparatively very long. its easier to hold a (2*8.5,11,2*5=17,11,17) compact box, because it will be easy to carry a long and not heavy.

7 0

3 years ago

The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab

kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable X can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable X thus follows a Poisson distribution with parameter, λ = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.

The mean of the approximated distribution of X is:

μ = λ = 250

The standard deviation of the approximated distribution of X is:

σ = √λ = √250 = 15.8114

Thus, $X\sim N(250, 250)$

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

$P(235$

$=P(-0.95$

Thus, the value of P (235 < X < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

$P(48$

$=P(-0.28$

Thus, the value of $P(48$ .

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

$P(48$

$=P(-0.40$

Thus, the value of $P(48$ .

(d)

Let the sample size be n.

$P(48$

$0.95=P(-z$

The value of z for this probability is,

z = 1.96

Compute the value of n as follows:

$z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241$

Thus, the sample selected must be of size 240.

5 0

3 years ago

An office that dispenses automotive license plates has divided its customers into categories to level the office workload. Custo

grigory [225]

Answer:

UNIF(2.66,3.33) minutes for all customer types.

Step-by-step explanation:

In the problem above, it was stated that the office arranged its customers into different sections to ensure optimum performance and minimize workload. Furthermore, there was a service time of UNIF(8,10) minutes for everyone. Since there are only three different types of customers, the service time can be estimated as UNIF(8/3,10/3) minutes = UNIF(2.66,3.33) minutes.

6 0

3 years ago