I'll try it.
I just went through this twice on scratch paper. The first time was to
see if I could do it, and the second time was because the first result
I got was ridiculous. But I think I got it.
You said <span><u>3sin²(x) = cos²(x)</u>
Use this trig identity: sin²(x) = 1 - cos²(x)
Plug it into the original equation for (x).
3(1 - cos²(x) ) = cos²(x)
Remove parentheses on the left: 3 - 3cos²(x) = cos²(x)
Add 3cos²(x) to each side: 3 = 4cos²(x)
Divide each side by 4 : 3/4 = cos²(x)
Take the square root of each side: <em>cos(x) = (√3) / 2</em> .
There it is ... the cosine of the unknown angle.
Now you just go look it up in a book with a table cosines,
or else pinch it through your computer or your calculator,
or else just remember that you've learned that
cos( <em><u>30°</u></em> ) = </span><span><span>(√3) / 2 </span>.
</span>
Answer:
D. 15
Step-by-step explanation:
Let the missing length be represented as x.
Thus:
(24 - x)/12 = x/20 => angle bisector theorem
Cross multiply
20(24 - x) = x(12)
480 - 20x = 12x
480 - 20x + 20x = 12x + 20x
480 = 32x
480/32 = 32x/32
15 = x
Missing length = x = 15
There are two critical points, at which we have
Answer:
please provide the diagram
