Answer:
By strengthening key elements of their safety and health programs, they also can improve their overall organizational performance. In addition to the social benefits, employers that use leading indicators to find and fix hazards can realize direct savings to their bottom line.
Before we calculate we can use some common sence thinknig to narrow down the choices. We know that Robert is gonig DOWN the hill, so it doesnt make sence that he woudl have a positive rate of change (i.e. the number feet up the hill he is is decreasing, not increasing) So right away, A & B are clearly wrong.
If we look at the last two (C & D) we can see that if -460 were right after 10 minutes he would have walked down 4,600 feet. This is WAY more that the total height of the hill and so can't be correct.
So C must be correct.
We can check this with some simple math:
Table of the graph:
x: <em>
</em>
1 2 3
y: 5 25 125
Average Rate of Change =

Section A = 25-5/2-1 =20/1 =20
Section B = 125 - 25/ 3-2 = 100/1 = 100
So, Section B is 5 times greater than A.
Section B is greater because the slope of two points is greater than points in Section A.
Answer:
The answer is below
Step-by-step explanation:
Mrs. Fielder decides to build a small snow shelter for her children to wait in before the school bus arrives in the morning. She has only enough wood for a total perimeter of 20 feet.
a. Make a table of all the whole number possibilities for the length and width of the shelter. Find the area of each shelter.
b. What dimensions should Mrs. Fielder choose to have the greatest area in her shelter?
c. What dimensions should Mrs. Fielder choose to have the least area in her shelter?
d. Township building codes require 3 square feet for each child in a snow shelter. Which shelter from part (a) will fit the most children? How many children is this? Explain your reasoning.
Solution:
a) Let W represent the width of the school shelter and let L represent the length of the school shelter. Therefore:
Perimeter of the school shelter = 2(length + breadth)
20 = 2(L + W)
L + W = 10
Also, the area of the school shelter = L * W
Length (ft) Width (ft) Area(ft²) = length * width
1 9 9
2 8 16
3 7 21
4 6 24
5 5 25
b) The shelter with a length of 5 ft and width of 5 ft has the largest area.
c) The shelter with a length of 1 ft and width of 9 ft has the least area.
d) The 4 by 6 ft shelter can hold 8 children (24 ft² / 3 ft² = 8) and the 5 by 5 ft shelter can hold 8 children with an extra space (25 ft² / 3 ft² = 8.33).