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professor190 [17]
3 years ago
9

Use the method illustrated in the solutions to Exercise 9.2.39 to answer the following questions. (a) How many ways can the lett

ers of the word DANCER be arranged in a row? Since the letters in the given word are distinct, there are as many arrangements of these letters in a row as there are permutations of a set with elements. So the answer is . (b) How many ways can the letters of the word DANCER be arranged in a row if D and A must remain together (in order) as a unit? (c) How many ways can the letters of the word DANCER be arranged in a row if the letters NCE must remain together (in order) as a unit?
Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0

Answer:

(a) 720 ways

(b) 120 ways

(c) 24 ways

Step-by-step explanation:

Given

Word = DANCER

n =6 --- number of letters

Solving (a): Number of arrangements.

We have:

n =6

So, the number of arrangements is calculated as:

Total =n!

This gives:

Total =6!

This gives:

Total =6*5*4*3*2*1

Total =720

Solving (b): DA as a unit

DA as a unit implies that, we have:

[DA] N C E R

So, we have:

n = 5

So, the number of arrangements is calculated as:

Total =n!

This gives:

Total =5!

This gives:

Total =5*4*3*2*1

Total =120

Solving (c): NCE as a unit

NCE as a unit implies that, we have:

D A [NCE] R

So, we have:

n = 4

So, the number of arrangements is calculated as:

Total =n!

This gives:

Total =4!

This gives:

Total =4*3*2*1

Total =24

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