Answer:
60 inches long are the sides of the pillars.
Step-by-step explanation:
Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.
To find : How many inches long are the sides of the pillars?
Solution :
Refer the attached picture below for Clarence of question.
The volume of the cube is 
Where, a is the side.
The combined volume of the four pillars is 500 ft cubed.
The volume of each cube is given by,
Substitute in the formula to get the side,
![a=\sqrt[3]{125}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7B125%7D)
We know, 1 feet = 12 inches
So, 5 feet =
inches
Therefore, 60 inches long are the sides of the pillars.
Answer:
about 1.56637 radians ≈ 89.746°
Step-by-step explanation:
The reference angle in radians can be found by the formula ...
ref angle = min(mod(θ, π), π -mod(θ, π))
Equivalently, it is ...
ref angle = min(ceiling(θ/π) -θ/π, θ/π -floor(θ/π))×π
<h3>Application</h3>
When we divide 11 radians by π, the result is about 3.501409. The fractional part of this quotient is more than 1/2, so the reference angle will be ...
ref angle = (1 -0.501409)π radians ≈ 1.56637 radians ≈ 89.746°
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<em>Additional comment</em>
For calculations such as this, you need to use the most accurate value of pi available. The approximations 22/7 or 3.14 are not sufficiently accurate to give good results.
Answer:
b = 3.1
Step-by-step explanation:
Since the length of one of the longer sides, a, has been given to be 6.3, plug it into the equation.
2(6.3) + b = 15.7
12.6 + b = 15.7
b = 15.7 - 12.6
Answer:
90.244
Step-by-step explanation:
111 ÷ 1.23 = 90.244
