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2 years ago

Question 9 of 15 (1 point)

Mathematics

1 answer:

mote1985 [20]2 years ago

7 0

The number is -9

Step-by-step explanation:

Let x be the number then according to given statement

$4x+10 = x-17$

Subtracting 10 from both sides

$4x+10-10 = x-17-10\\4x = x-27$

Subtracting x from both sides

$4x-x = x-x-27\\3x = -27$

Dividing both sides by 3

$\frac{3x}{3} = \frac{-27}{3}\\ x = -9$

Verification:

$4(-9)+10 = -9-17\\-36+10=-26\\-26=-26$

The number is -9

Keywords: Linear equation, variables

Learn more about linear equation at:

#learnwithBrainly

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Please help asap!! Thank you

djyliett [7]

Step-by-step explanation:

Hey, there!!

Let's simply work with it,

60° + 2x° + (2x+12)° = 180° { being a linear pair}.

or, 72° + 4x = 180°

4x = 180° - 70°

$x = \frac{108}{4}$

Therefore, the value of x is 27°.

Now,

2x° = (2×27)°= 54°

(2x+12)° = 2×27°+12°= 66°.

(x+2)= 27+ 2= 29°

Now, The left angle is 27°.

Therefore, The answer is option A.

Hope it helps...

6 0

3 years ago

Vector V is shown in the graph below.

Lady_Fox [76]

Answer:

v = -8i - 6j

Step-by-step explanation:

The starting point is (9, 9)

The direction of the vector is the direction of the arrowhead.

The i is the horizontal component.

The j is the vertical component.

Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).

Therefore, v = -8i - 6j

8 0

2 years ago

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What is the equation of the line that passes through the points (-1, 3) and (1, 11)

lina2011 [118]

Answer: To find the slope of this line, you would use the fomula

y2 - y1/ x2 - x1

11 - 3 / 1 - (-1)=

8/2

The slope of your line would be 4

3 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

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3 years ago

100% De

Gemiola [76]

Answer:

$1.75 because if u add $3.50 + $1.75 u get $5.25 subtract that from $7.00 u get $1.75

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3 years ago

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