Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
471.2 cm³ missing
Step-by-step explanation:
jars are cylinders
volume of cylinder = π * r² * h
h=10
r=5
v=785.4 cm³ of a full jar
r stays the same = 5
h = 4
v= 314.2 cm³ left in the jar
whats missing is the full-left
785.4-314.2=471.2 cm³ missing
(2√5 + 3(√7))^2
(2√5 + 3(√7))(2√5 + 3(√7))
4*5 + 6√35 + 6√35 + 9*7
20 + 12√35 + 63
20 + 63 + 12√35
83 + 12√35
There would be 14 female and 7 male, so the total number of students is 21.
Answer:
(btw the first question answer is -4, not 0)
10
Step-by-step explanation:
(btw the first question answer is -4, not 0)
So to solve the 2nd equation you substitute t with 30
so 30-2/3*30
30-20=10
