
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
Answer: 32002544
Step-by-step explanation:
B) If A x B = {(-1, 1), (-1, 2), (2, 1), (2, 2), (3, 1), (3, 2)}. Find A x A and B x B.
Oduvanchick [21]
hope this helps!
Step-by-step explanation:
A = {-1, 2, 3}
B = {1,2}
AxA = {(-1,-1) (-1,2) (-1,3) (2,-1) (2,2) (2,3) (3,-1) (3,2) (3,3)}
BxB = {(1,1) (1,2) (2,1) (2,2)}
Four scarves and six hats is $52.00
<span>4s+6h=52 </span>
<span>two hats is $1.00 more than the cost of one scarf. </span>
<span>2h=1s+1 </span>
<span>2h=s+1 </span>
<span>s=2h-1 </span>
<span>substitute for s </span>
<span>4s+6h=52 </span>
<span>4(2h-1)+6h=52 </span>
<span>8h-4+6h=52 </span>
<span>14h=56 </span>
<span>h=4 </span>
<span>s=2h-1 </span>
<span>s=8-1 </span>
<span>s=7 </span>
<span>a scarf cost $7 </span>
<span>a hat cost $4</span>