Discriminant = sq root of b^2 - 4*a*c =
sq root of 36 - 4*1*13 =
sq root 36 -52 =
sq root 36 -52 =
sq root -16
There are no real solutions for this equation. Both roots are complex numbers.
1 byte9 Cube root of b^27 = b^27/3 = b^9.
Answer:
It should be option B
Step-by-step explanation:
-x+26=2x-10
+x +10 +x +10
36+3x
divde by 3
12=x
m∠D=2(12)-10
=24-10
=14
Hey There!
Here is your answer:
First write the equation down:
-3 4/5 ÷ -3 1/6
Then put the mixed fractions into whole numbers:
-3 4/5= 5×-3=-15+4=-11= -11/5
&
-3 1/6= 6×-3=-18+1=-17= -17/6
Now right the new problem:
-11/5×6/-17
Now multiply:
-11×6=-66
5×-17=-85
Which means -66/-85 is your answer!
Hope this helps!
