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kolbaska11 [484]
3 years ago
14

Answer needed ASAP !!!

Mathematics
2 answers:
GalinKa [24]3 years ago
8 0

Answer:

i think its b 96

Step-by-step explanation:

idk i used a calculator lol

dsp733 years ago
6 0

I think the answer is 96.


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All Major League Baseball stadiums use standard measurements for their infield area. The pitcher's mound is a circle with a diam
denis-greek [22]

Answer:

254 4/7 or 254.34 ft² (it depends on which method you use.)

Step-by-step explanation:

To find the area of a circle, the formula is πr².

I'll use both 22/7 and 3.14 as pi, so I'll end up with two different answers. Just choose the more reliable one.

22/7 version:

22/7 * 9^2

22/7 * 81/1

1782/7

254 4/7 ft²

3.14 version:

3.14 * 9^2

3.14 * 81

314 - (3.14 * 19)

314 - 62.8 + 3.14

251.2 + 3.14

254.34 ft²

As I said, I ended up with two different answers. You also had said not to round my answer, so the 22/7 version has a mixed number.

5 0
3 years ago
In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

6 0
3 years ago
Can you check my answers and help with number 3?
mamaluj [8]

Answer: Question 1 :B,D.

Question 2:option B,

Question 3:Degree=5.

Question 4:option D.

Question 5: option c.


Step-by-step explanation:

1) A polynomial can not have any exponent as a variable or a fraction.

Options B and D are polynomials.

2) The polynomial is having 3 terms and is of degree 3.so it is a cubic trinomial Option B.

3) Degree is the highest power of the variables in the terms .The term 6x^{3} y^{2} has the power=3+2=5

So degree =5.

4)(5x-2+3x^{2} )+(4x+3)=3x^{2} +5x+4x-2+3=3x^{2}+9x+1.

Option D


5)(5x^{2} +2x-5)-(3x^{2}+3x+1)= 5x^{2}+2x-5-3 x^{2}-3x-1

Simplifying like terms,

=2x^{2}-x-6.

Option c.


6 0
2 years ago
HELP!!<br>What is the surface area of this shape?​
Hunter-Best [27]

2 triangular faces

1/2bh

10x15=150

2x150= 300

‘back’ face

7x20=140

‘front’ face

7x25= 175

‘bottom’ face

7x15= 105

total: 585m^2

6 0
3 years ago
Help me please this is very important to me for rbainlist and explain
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

The probability of getting one even and one odd is the sum of probability of getting even and of getting odd and even. Since there are 3 even or odd on each die out of six numbers you have

P(EO)(3/6)(3/6)=1/4 and P(OE)=(3/6)(3/6)=1/4 so 1/4+1/4= 1/2

or you can find the probability of getting two odds or two evens and subtract that from 1

P(EE)=(3/6)(3/6)=1/4, P(OO)=(3/6)(3/6)=1/4

P(EO)=1-1/4-1/4=1/2

6 0
3 years ago
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