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Alex Ar [27]
3 years ago
8

F(x) = 4x + 5 g(x) = -10x² + 8x – 7 Find: f(x) · g(x)

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

G(x) =0.4/0.7

F(x)= 6.6/14

Step-by-step explanation:

G(x)= 0.4/0.7

F(x)= 4(0.4)+5

=6.6

4(0.7)+5

=14.

Dm me if I'm wrong. If not, please mark as brainliest

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On a test, you earn 92% of the possible points by correctly answering 6 five-point questions and 8 two-point questions. How many
olya-2409 [2.1K]

Step-by-step explanation:

(6×5)+(8×2)=46

92℅=46points

100℅=x

criss cross

<u>92℅x=46</u>

<u>9</u><u>2</u><u>℅</u><u>.</u><u> </u> 92℅

and this is the answer

8 0
3 years ago
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Which equation can be used to find the measurement of ∠C? To the nearest degree, what is the measurement of ∠A? A) 5sin∠C = 2; 2
egoroff_w [7]
First guy is incorrect.Answer is actually B

7 0
3 years ago
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It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
How to solve inequalities
shepuryov [24]

Answer:An absolute value inequality is solved by re-writing it as compound inequality. For example.

|x+1| < 5

Since the value inside the absolute value brackets: (x+1) can be positive or negative, it is re-written as a compound inequality as the example below.

x+1 < 5

x+1 > - 5

solve for the range of values x can be

-6 < x < 4

Step-by-step explanation: How to solve inequalities

4 0
3 years ago
Which trigonometric functions are negative in the fourth (IV) quadrant?
anzhelika [568]
<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

Explanation:

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Since sine is negative, so is cosecant as this is the reciprocal of sine

csc = 1/sin

In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.

Because tangent is negative, so is cotangent.

The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.

7 0
3 years ago
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