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Anestetic [448]
2 years ago
12

P:-3x + 8x - 5x = x q: (3x)(5y) = 15xy Which of the following statements is false?

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
5 0

Answer: Statement p is false.

Step-by-step explanation:

In both cases, we need to isolate the variables:

p: -3*x + 8*x - 5*x = x

   (-3*x - 5*x) + 8*x = x

    -8x + 8*x = x

        0 = x

This will be true only for one value of x, so this is not always true, which means that the statement is false.

q: (3*x)*(5*y) = 15*x*y

let's solve the left side:

  3*x*5*y = 15*x*y

  (3*5)*(x*y) = 15*x*y

   15*x*y = 15*x*y

This is true for every value of x and y, then this statement is true.

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Answer:

1 2/3 = m

Step-by-step explanation:

2/3 = m+3/5 -8/5

Combine terms

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Add 1 to each side

2/3 +1 = m-1+1

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4 0
3 years ago
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A Scientist had a bottle that contains 56.6 mL of solution.She used 3.2 mL of the solution for an experiment.She poured half of
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56.6 - 3.2 = 53.4
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7 0
3 years ago
(b) A line has the equation y = 6x + 11
marin [14]

Hi, to begin, the ordered pair value (-3, 15) has an x-value of -3. So, to see if it lies on the line of your equation y = 6x + 11, plug -3 in for x. This gives you y = 6(-3) + 11 = -7 So the ordered pair answer for this would be (-3, -7) and not (-3, 15). So the answer is no.

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2 years ago
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Prove that a triangle with the sides a - 1 cm to root under a ​
vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.  

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm  

Hence,

{AB}^2 = (a -1)^2 

Now We know that

(a- b)^2 = a^2+b^2 - 2ab

So;

{AB}^2= a^2 + 1^2 -2\times a \times1

{AB}^2 = a^2 + 1 -2a

Now;

{BC}^2 = (2\sqrt{a})^2= 4a

Also;

{CA}^2 = (a + 1)^2

Now We know that

(a+ b)^2 = a^2+b^2 + 2ab

{CA}^2= a^2 + 1^2 +2\times a \times1

{CA}^2 = a^2 + 1 +2a

{CA}^2 = AB^2 + BC^2

[By Pythagoras theorem]

a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a

Hence, {CA}^2 = AB^2 + BC^2

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0
3 years ago
2x^2 - 3x^2 - 4 + 6. pls Help Me ASAP .
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