Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Forgive me if this is wrong. I haven't done stat in a year, but comment if you need clarification!
Albert bought 2 pounds of catfish and 2 pounds of salmon
Let c represent the amount of catfish in pounds and s represent the amount of salmon in pounds.
He spent a total of $12 on salmon and catfish and bought a total of 4 pounds. Hence:
c + s = 4 (1)
4c + 2s = 12 (2)
Solving equations 1 and 2 simultaneously gives:
c = 2, s = 2
Albert bought 2 pounds of catfish and 2 pounds of salmon
Find out more on equation at: brainly.com/question/2972832
Answer:
the cyan one b is greater than or equal to -16
Step-by-step explanation:
okay so b is at least (at least being the keyword) -16, at least means that -16 is the minimum
hope this helps:)
Answer:0
Step-by-step explanation:
You distribute the 4 on 5&x which will then be 20. Your equation is now 20+4x=20 you then subtract the twenty so then it’s 4x=0 divide by 4 on both sides which gives you 0
