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mars1129 [50]
4 years ago
15

How do I solve this problem and what's the answer

Mathematics
1 answer:
alexandr402 [8]4 years ago
7 0
First diver isat -30
2nd is at -5

distance between -5 and -30 is
|-30-(-5)|=|-30+5|=|-25|=25
the distance is 25 meters
B
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A baker lives 11 blocks away from the store. The baker walks to the store and back, taking a two block teacher each way. How man
Alisiya [41]
22 blocks is the answer
6 0
3 years ago
5x^2+15=51; square root property
charle [14.2K]
1. Subtract 15 to the other side (5x^2 = 36)

2.Square root both sides to remove the squared of 5x^2 (sqrt(5x^2) = sqrt(36) simplified to 5x = 6)

3. divide by 5 to get x = 6/5

Final result is 6/5
7 0
3 years ago
Plsss help fast please!!!
Ahat [919]
5. 2/1 6. 1/-2 7. 2/-3

5 0
4 years ago
BRAINLIEST to the best answer with a good explanation!
butalik [34]

Answer:

£15.10

x + 20

64 counters in the bag

Total money = £21.30

Step-by-step explanation:

20p = £0.20

50p = £0.50

100p = £1.00

Total value:

⇒ 8 × 20p + 5 × 50p + 11 × £1 = 8 × 20p + 5 × 50p + 11 × 100p

                                                = 160p + 250p + 1100p

                                                = 1510p

                                                = £15.10

-----------------------------------------------------------------------------------------------------

20 more than x:   x + 20

-----------------------------------------------------------------------------------------------------

If one quarter of the counters in a bag are yellow, and there are 16 yellow counters in the bag:

⇒ total number of counters in the bag = 16 × 4 = 64

-----------------------------------------------------------------------------------------------------

Let x = number of 20p coins

Let y = number of 50p coins

Let z = number pf £1.00 coins

Given:

  • 20p coins are worth £2.80

⇒ 0.20x = 2.80

⇒ x = 2.80 0.20

⇒ x = 14

Therefore, there are 14 twenty pence coins.

Given:

  • One third of the coins are 20p coins

We have calculated that there are 14 twenty pence coins, therefore:

⇒ total number of coins = number of 20p × 3            

                                        = 14 × 3

                                        = 42

As the total number of coins is 42:

⇒ x + y + z = 42

⇒ 14 + y + z = 42

⇒ y + z = 42 - 14

⇒ y + z = 28

Therefore, the total number of 50p and £1 coins is 28.

Given:

  • 10 more 50p coins than £1 coins

⇒ y = z + 10

Substitute  y = z + 10  into y + z = 28 and solve for z:

⇒ (z + 10) + z = 28

⇒ 2z + 10 = 28

⇒ 2z = 18

⇒ z = 9

Therefore, there are 9 one pound coins

total number of coins:

⇒  x + y + z = 42

substituting the found values of x and z:

⇒  14 + y + 9 = 42

⇒  23 + y = 42

⇒  y = 19

Therefore, there are 19 fifty pence coins

20p coins = 14

50p coins = 19

£1 coins = 9

Therefore, total money:

= 14 × 20p + 19 × 50p + 9 × 100p

= 280p + 950p + 900p

= 2130p

= £21.30

3 0
3 years ago
State, with an​ explanation, whether the​ mean, median, or mode gives the best description of the following average. The average
erma4kov [3.2K]

Answer:

The mean is the better method.

Step-by-step explanation:

The best way to meassure the average height is throught mean. The mean of a sample is the average of that sample's height, and it will be a good estimate for the population's average height.

The mode just finds the most frequent height. Even tough the most frequent height will influence the average height, knowing only what height is the most frequent one doesnt give you enough informtation about how the height is centrally distributed.

As for the median, it is fine to use the median of a sample to estimate the median of the population, but if you use the median to estimate the average height you may have a few issues. For example, if you include babies in your population, the babies will push the average height down a lot and they are far below te median height. This, as a result, will give you a median height of a sample way above the average height of the population, becuase median just weights every person's height the same, while average will weight extreme values more, in the sense that a small proportion of extreme values can push the average far from the median.

8 0
3 years ago
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