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sergiy2304 [10]
2 years ago
15

I need help with 2&3

Mathematics
1 answer:
devlian [24]2 years ago
5 0

Answer:

2. A 4√3

3. B -5/3

Step-by-step explanation:

You might be interested in
What Is 5 1/2 - 2 5/6? Explain Your Answer
natulia [17]

Answer:

2 2/3

Step-by-step explanation:

Make them into improper fractions first.

11/2 - 17-6

Then multiply 11/2 so that they have common denominators.

33/6 - 17/6

Then solve.

33/6 - 17/6 = 16/6

Then convert back into a mixed number.

2 4/6 or 2 2/3

5 0
3 years ago
Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.
Serga [27]

Answer:

Yes

Step-by-step explanation:

ΔMNL ≅ ΔQNL  by ASA or AAS

by ASA

Proof:

∠ LNM = ∠LNQ    =90

LN = LN   {Common}

∠MLN = ∠QLN     {LN bisects ∠ L}

By AAS

∠Q + ∠QLN + ∠LNQ = 180  {Angle sum property of triangle}

∠Q + 32 + 90 = 180

∠Q  + 122 = 180

∠Q = 180 -122 =

∠Q = 58

∠Q = ∠M

∠MNL =∠QNL = 90

LN = LN {common side}

8 0
3 years ago
A study found that average there were 566,000 tweets per hour using this data how many tweets are there per minute
Mazyrski [523]

Answer:

D

Step-by-step explanation:

566,000/60 = 9433 1/3 = 9433.3

7 0
3 years ago
Three students collected more than $93 washing cars. They used $15 to reimburse their parents for cleaning supplies. Then they d
Alenkasestr [34]
First step is find profit so lets subtract 93 and 15.
93-15=78
Finally we can divide profit by 3 students, so
78:3=26$ its the answer
4 0
3 years ago
Read 2 more answers
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
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