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Nookie1986 [14]
3 years ago
6

Select all that are true for the graph that represents the function f(x)=5(3)^x

Mathematics
1 answer:
fiasKO [112]3 years ago
4 0

Answer:

F. as x decreases, y approaches 0.

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Find the length of side a<br><br> a A. 12 <br>B. 144 <br>C. 1 194 <br>D. 8​
lukranit [14]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
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The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0
3 years ago
I need it ASAP! Will ran 3.23 km the first week and 4.15 km the second week. Chuck ran 8.75 km in two weeks.
andreev551 [17]
D. About 1.4 km hope this helps ;)
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3 years ago
A person 2.1 m tall casts a shadow 5.3 m long. At the same time, a building casts a shadow 34
bulgar [2K]
Height. Shadow
2.1 m. 5.3 m
X m. 34 m
X=2.1•34/5.3
X=71.4/5.3
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3 years ago
There are 15 trucks, 4 cars, and 2 buses in the parking lot. What is the ratio of cars to buses
storchak [24]
4:2 because it goes cars then buses
7 0
3 years ago
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