All categories

3 years ago

The segment shown below could form a triangle. True or False

Mathematics

2 answers:

Hatshy [7]3 years ago

8 0

Answer:

Yes, this can form a triangle.

Step-by-step explanation:

As long as the two shorter legs' sum IS NOT GREATER THAN the length of the larger segment, then a triangle can be formed! As we can see, 6 + 5 = 11, which is less than 12.

Tanzania [10]3 years ago

4 0

True! If you have any 3 segments, it could form a triangle, just not a right triangle.

You might be interested in

What is the value of x? A.31 B.41 C.29 D.60

Oksana_A [137]

your answer is c 29. To figure this out take 59-180= 121. Then add 121 and 30 =151. next subtract 151 from 180 and you get C 29

7 0

3 years ago

Plz help due tonight!!!

jolli1 [7]

Answer:

x=75+36

x=111

Step-by-step explanation:

pls mark as brainliest

7 0

2 years ago

Read 2 more answers

Jan has a 12 ounce milkshake. Four ounces in the milkshakes are vanilla, and the rest is chocolate. What equivalent fractions th

Thepotemich [5.8K]

Answer:

Vanilla milkshake = 1/3 and Chocolate milkshake = 2/3

Step-by-step explanation:

Given data:

Total ounce of milkshake = 12 ounce

Vanilla milkshake = 4

Chocolate is the rest which can be interpreted as 12 - 4= 8 ounce

Representing as fractions

Vanilla milkshake = 4/12 (Reducing to lowest terms that is diving numerator and denominator by common factor in this case 4)

Vanilla milkshake = 1/3

Chocolate milkshake = 8/12 (Reducing to lowest terms that is diving numerator and denominator by common factor in this case 4)

Chocolate milkshake = 2/3

5 0

3 years ago

Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A

liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality $\sin ^2\theta +\cos ^2\theta \geq 1$

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

$\sin \theta$ = side opposite to $\theta$ /hypotenuse

$\cos \theta$ = side adjacent to $\theta$ /hypotenuse

$\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta$

$\cos \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta$

So, coordinates of A = $\left ( \cos \theta ,\sin \theta \right )$

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by $x^2+y^2=1$

Put $(x,y)=\left ( \cos \theta ,\sin \theta \right )$

$\cos ^2\theta +\sin ^2\theta =1$

So, $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ satisfies the equation $x^2+y^2=1$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ inside the circle, $\cos ^2\theta +\sin ^2\theta$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ outside the circle, $\cos ^2\theta +\sin ^2\theta >1$

So, only points on the circle satisfy the given inequality.

4 0

2 years ago

Read 2 more answers

List 3 values that would make this inequality true. 3n < 18

emmasim [6.3K]

First it has a sign second is that you can divide 3 by 18 and lastly 18 is greater than 3n

5 0

3 years ago