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3 years ago

Write in standard form (100 x 3)+(4 x 0.1)+(7 x 0.001)

Mathematics

1 answer:

Taya2010 [7]3 years ago

3 0

Answer:

300.407

Step-by-step explanation:

100*3=300

4*0.1=0.4

7*0.001=0.007

----------------------

300+0.4+0.007

300.407

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The width of a rectangle is 15 ft. shorter than its length. Its perimeter is 262 ft. Let l equal the length of the rectangle.

masha68 [24]

Let the length be l.
For now, let's make the width be w.
Additionally, l = w + 15. Using this equation, width can also be written as l - 15.
The perimeter of a rectangle is length + length + width + width. This can also be written as l + l + (l-15) + (l-15) = l + l + l - 15 + l - 15 = 4l - 30.
Using this equation:
4l - 30 = 262
4l = 292
l = 73

4(w + 15) - 30 = 262
4w + 60 - 30 = 262
4w + 30 = 262
4w = 232
w = 58

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3 years ago

The equation y+6=1/3(x-9) is written in point- slope form. What is the equation written in slope-intercept form?

kvv77 [185]

Your answer would be option three, y = 1/3 x -9 :)

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3 years ago

One line passes through the points (-4, 2) and (0, 3); another line passes through the points

Luba_88 [7]

Answer:

how are you working on a saturday night?

Step-by-step explanation:

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3 years ago

PQR is a right angled triangle calculate the size of angle marked x

romanna [79]

Answer:

$\displaystyle x \approx 37.4^\circ$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Define

Angle θ = x

Adjacent Leg = 5.8

Hypotenuse = 7.3

Step 2: Solve for x

Substitute in variables [Cosine]: $\displaystyle cosx^\circ = \frac{5.8}{7.3}$
[Fraction] Divide: $\displaystyle cosx^\circ = 0.794521$
[Equality Property] Trig inverse: $\displaystyle x^\circ = cos^{-1}(0.794521)$
Evaluate trig inverse: $\displaystyle x = 37.39^\circ$
Round: $\displaystyle x \approx 37.4^\circ$

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2 years ago

Is y=3x-5 and 6x=2y+10 a solution

iVinArrow [24]

Y=3x-5
y-3x=-5
Times 2 from both side
y(2)-3x(2)=-5(2)
2y-6x=-10
Times negative from both side
(-)2y-6x(-)=(-)-10
-2y+6x=10
or
6x-2y=10

6x=2y+10
6x-2y=10
Furthermore, we see that both equation have the same 6x-2y=10 which means that both of them have infinity solutions, not a solution. Hope it help!

5 0

3 years ago

Write in standard form (100 x 3)+(4 x 0.1)+(7 x 0.001)​

Write in standard form (100 x 3)+(4 x 0.1)+(7 x 0.001)