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vfiekz [6]
3 years ago
11

El color marrón en los ojos está determinado por el alelo M. Una mujer de ojos marrones cuya madre tenía los ojos azules y cuyo

padre era Homocigótico, decide tener 4 bebés con un hombre de ojos marrones. El padre de éste también tenía los ojos azules y su madre era Homocigótica. La presencia de color marrón en los ojos domina sobre el azul.
Biology
1 answer:
hoa [83]3 years ago
7 0

Explanation:

Here's a clearer rendering of text;

"The brown color in the eyes is determined by the M allele. A brown-eyed woman whose mother had blue eyes and whose father was Homozygous, decides to have 4 babies with a brown eyed man. His father also had blue eyes and his mother was homozygous. The presence of brown in the eyes dominates the blue".

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Answer:

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Explanation:

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So first of all, this looks like a dihybrid cross, but it is not because we are dealing with one pair of alleles (gene that causes sickle cell), so we will actually be doing a monohybrid cross.

So let’s go through the alleles step by step:

Hb = hemoglobin (constant, all red blood cells have hemoglobin, we are looking at the mutation in the beta globin gene of the hemoglobin which will be the allele we focus on)

SS = sickle cell (mutated beta globin gene (S) x 2)

AA = normal beta globin gene (A) x 2 (no sickle cell)

AS = carrier (one sickle cell gene + one normal gene)

HbAS x HbAS

Carrier x carrier

PARENTS A S

   A               AA AS

  S               AS SS

25% chance that the offspring will have a normal (does not have sickle cell anemia) genotype (AA)

50 % chance that the offspring will be carriers (AS)

25% chance that the offspring will have sickle cell anemia (SS)

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