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egoroff_w [7]
3 years ago
6

The domain of a function is always equal to which one of the following options?

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Answer:

B, all possible input values of the function.

Step-by-step explanation:

Functions assign outputs to inputs. The domain of a feature is the set of all possible inputs for the characteristic. For example, the domain of f(x)=x² is all real numbers, and the area of g(x)=1/x is all real numbers except for x=zero. We can also outline special features whose domain names are extra limited.

The area of a characteristic is the set of numbers which could pass into a given characteristic. In different phrases, it is the set of x-values that you can placed into any given equation. The set of viable y-values is called the range

Ivanshal [37]3 years ago
3 0

Answer:

all possible input values to the function

Step-by-step explanation:

The domain is the input to the function and the range is the output of the function

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Step-by-step explanation:

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3 years ago
what is (a) the lateral area and (b) the total surface area of a regular square pyramid with the length of each edge equal to 6?
Serhud [2]

Answer:

• lateral area: 36√3 square units

• total surface area: (36 +36√3) square units

Step-by-step explanation:

The area of an equilateral triangle of side length s is given by ...

A = (√3)/4·s^2

Your pyramid has four (4) such faces of side length 6 units, so the total (lateral) area of the triangular faces is ...

LA = √3·(6 units)^2 = 36√3 square units

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Of course the area of the square base is simply the square of its edge length, so is ...

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That means the total surface area, the lateral area plus the base area, is ...

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6 0
3 years ago
What is the zero of y=-4x^2+8x-28
tangare [24]

Solution, y-4x^2+8x-28=0:\quad \mathrm{Parabola\:with\:vertex\:at}\:\left(h,\:k\right)=\left(1,\:24\right),\:\mathrm{and\:focal\:length}\:|p|=\frac{1}{16}

Steps:

\mathrm{Rewrite}\:y-4x^2+8x-28=0\:\mathrm{in\:the\:standard\:form}

\mathrm{Rewrite\:as}, y=4x^2-8x+28

\mathrm{Complete\:the\:square}\:4x^2-8x+28:\quad 4\left(x-1\right)^2+24, y=4\left(x-1\right)^2+24

\mathrm{Subtract\:}24\mathrm{\:from\:both\:sides}, y-24=4\left(x-1\right)^2

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4, \frac{1}{4}\left(y-24\right)=\left(x-1\right)^2

\mathrm{Rewrite\:in\:standard\:form}, 4\cdot \frac{1}{16}\left(y-24\right)=\left(x-1\right)^2

\mathrm{Therefore\:parabola\:properties\:are:} \left(h,\:k\right)=\left(1,\:24\right),\:p=\frac{1}{16}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-\:austint1414}

8 0
3 years ago
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