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notsponge [240]
3 years ago
10

Find the nth term of the following sequence -5 ,-2, 3 ,10 ,19

Mathematics
2 answers:
Kryger [21]3 years ago
8 0

Answer:

30

Step-by-step explanation:

the sequence move in odd numbers firstly from -5 to -2 to +3 to 10 to 19

so the next term will be the next odd number which is 11

19 + 11

= 30

anygoal [31]3 years ago
7 0

Answer:9

Step-by-step explanation: the sequence move in odd numbers firstly from

-5 to -2 that is +3, -2 to 3 that is +5 and so on

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Jay places $3200 in an investment account earning 4.1% interest compounded weekly. How much money would he have in the account a
jasenka [17]

Answer:

A = $3,926.71

Step-by-step explanation:

Given: Principal (P) = $3200, Annual Rate (R) = 4.1%, Time = 5 years

To find: How much money would he have in the account after 5 years, if he made no deposits or withdrawals during that time?

Formula: A = P(1 + r/n)^nt

Solution: Compound interest is one of the most important concepts to understand when managing your finances. It can help you earn a higher return on your savings and investments, but it can also work against you when you're paying interest on a loan

First, convert R as a percent to r as a decimal

r = R/100

r = 4.1/100

r = 0.041 rate per year,

Then solve the equation for A

A = P(1 + r/n)^{nt}

A = 3,200.00(1 + 0.041/12)^{(12)(5)}

A = 3,200.00(1 + 0.003416667)^{(60)}

A = $3,926.71

Hence, Jay would have $3,926.71 after 5 years is if he made no deposits or withdrawals during that time.

3 0
3 years ago
PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

8 0
3 years ago
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DiKsa [7]

Answer:

These equations are equivalent because after you solve the equation the answer are the same. For example 2+2 and 3+1 are equivalent. They both equal four. In these problems are x=3 and x=3.5 they are the same beause of the answer on problem 2 6-x. That makes them both have the same answer

Step-by-step explanation:

7x-9=12

   +9=+9

   7x=21

   /7=/7

   x=3                                

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Elena-2011 [213]
10% of what is 9...
0.10x = 9
x = 9/0.10
x = 90.....he has 90 all together
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Express -3/6 as a rational number with denominator 20​
Usimov [2.4K]

Answer:

20 cause when According to Sciencealert, the longest math equation contains around 200 terabytes of text. Called the Boolean Pythagorean Triples problem, it was first proposed by California-based mathematician Ronald Graham, back in the 1980s.The Navier-Stokes equation, for me is the hardest of all. This is the full Navier-Stokes equation in conservative form. It looks pretty simple, but as one will dig in, they will notice why it is the hardest one.

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3 years ago
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