Answer:
The answer is below
Step-by-step explanation:
The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.
Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.
The loan must be at least for 5.72 years for an annual interest rate (r) of 10%
Answer: seven and twenty-five hundredths
Step-by-step explanation:
just need to know how to say it
Answer:
x = 200
Step-by-step explanation:
Multiply by 4:
x + 120 + 2x = 720
3x = 600 . . . . . . collect terms, subtract 120
x = 200 . . . . . . . divide by 3
_____
<em>Check</em>
(200/4 +30) +(200/2) = 180
(50 +30) + 100 = 180
80 + 100 = 180 . . . . . true
_____ _____
<em>Alternate solution</em>
If you like, you can simply work with the equation given.
(3/4)x + 30 = 180 . . . . collect terms
(3/4)x = 150 . . . . . . . . . subtract 30
x = 200 . . . . . . . . . . . . multiply by 4/3
Answer:
Option C and Option D have exactly one solution.
Step-by-step explanation:
The equation will have exactly one solution when it completely solves and we get value of x.
Checking all choices
(Choice A)
-19x + 18 = -19x + 18
-19x+19x=18-18
0=0
(infinite solutions)
(Choice B)
-19x -18 = -19x + 18
-19x+19x=18+18
0≠36
(no solution)
(Choice C)
19x + 18 = -19x + 18
19x+19x=18-18
38x=0
x=0
(One solution)
(Choice D)
19x - 18 = -19x + 18
19x+19x=18+18
38x=36
x=36/38
x=18/19
(One solution)
So, Option C and Option D have exactly one solution.
