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2 years ago

What is the prime factorization of 81m^2 x^3? A) 9^2 • m^2 • x^3 B) 3^3 • m^2 • x^3 C) 3^3 • m • x D) 3^4 • m^2 • x^3

Mathematics

1 answer:

Diano4ka-milaya [45]2 years ago

8 0

$81m^2x^3=3^4\cdot m^2\cdot x^3\to\boxed{D.}$

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Please help me out solve it and tell me how you got that answer so I can understand please!

NikAS [45]

The solution for s in the given equation is $s = C-nD$

The question seems to be incomplete

Here is the complete question:

Solve for s in this equation $D= \frac{C-s}{n}$ Depreciation.

To solve for s, that means we should make s the subject of the equation

From the given equation,

$D= \frac{C-s}{n}$

To solve for s, first multiply both sides by n to clear the fraction

We get

$n\times D= n \times \frac{C-s}{n}$

Then,

$nD = C - s$

Now, add s to both sides

$nD + s= C - s+s$

$nD+s = C$

Then, subtract nD from both sides

$nD-nD+s = C-nD$

∴ $s = C-nD$

Hence, the solution for s in the given equation is $s = C-nD$

Learn more here: brainly.com/question/21406377

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Answer:

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