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Wewaii [24]
3 years ago
7

What is the prime factorization of 81m^2 x^3? A) 9^2 • m^2 • x^3 B) 3^3 • m^2 • x^3 C) 3^3 • m • x D) 3^4 • m^2 • x^3

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

81m^2x^3=3^4\cdot m^2\cdot x^3\to\boxed{D.}

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Can you Solve. 3x^2+10x+3
Alika [10]
You cannot solve for x but you can factor

to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y

so solve

3 times 3=9

what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so

3x^2+1x+9x+3
(3x^2+1x)+(9x+3)
factor
(x)(3x+1)+(3)(3x+1)
reverse distribute
ab+ac=a(b+c)

(x)(3x+1)+(3)(3x+1)=(x+3)(3x+1)
factored out form is (x+3)(3x+1)

6 0
3 years ago
Read 2 more answers
How many times will the string literal "Hi" appear in the lblMsg control? Dim intCount As Integer Do While intCount > 4 lblMs
4vir4ik [10]

Answer:

0

Step-by-step explanation:

In my opinion, the string won't display because, the intCount was not initialized before you started outputting the "Hi" string. So in order fro you to get the string to appear, the control point or value has to be initialized to maybe 0. then you can start looping from there. And if you are looping from the top or using greater than (>), The loop works best buy subtracting the control value else, you can end up with infinity loop.

6 0
3 years ago
Alana and two of her friends evenly split the cost of a meal. each person owes $14.68.
True [87]

Answer:

$44.04

Step-by-step explanation:

14.68 * 3 = 44.04

8 0
3 years ago
What mistake did she make?
tiny-mole [99]

Step-by-step explanation:

According to the pythagrean equation, it should be

AC^2 = AB^2 + BC^2\\

8² = 6² + BC²

64 = 36 + BC²

BC² = 28

BC = ✓28 = 5.29

7 0
2 years ago
Hat is the solution to the equation 3/3(4c + 16)=2c+9 ?<br><br> c =
marusya05 [52]
If it is \frac{3}{3(4c+16)}=2c+9, go to AAAAAA
if it is (\frac{3}{3})(4c+16)=2c+9, go to BBBBB

AAAAAAAAA
\frac{3}{3(4c+16)}=2c+9
\frac{1}{4c+16}=2c+9
times 4c+16 to both sides
1=(2c+9)(4c+16)
distribute
1=8c^2+68c+144
minus 1 both sides
0=8c^2+68c+143
use quadratic formula
c=\frac{-17- \sqrt{3} }{4} or \frac{-17+ \sqrt{3} }{4}




BBBBBBBBBBBB
(3/3)(4c+16)=2c+9
1(4c+16)=2c+9
4c+16=2c+9
minus 2c both sides
2c+16=9
minus 16 both sides
2c=-7
divide both sides by 2
c=-7/2
c=-3.5





if it is \frac{3}{3(4c+16)}=2c+9,
c=\frac{-17- \sqrt{3} }{4} or \frac{-17+ \sqrt{3} }{4}


if it is (\frac{3}{3})(4c+16)=2c+9, c=-3.5



7 0
3 years ago
Read 2 more answers
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