Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>
![A=p\left(1+\frac{r}{100}\right)^{n}](https://tex.z-dn.net/?f=A%3Dp%5Cleft%281%2B%5Cfrac%7Br%7D%7B100%7D%5Cright%29%5E%7Bn%7D)
Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get
![\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}](https://tex.z-dn.net/?f=%5Cmathrm%7BA%7D%3D3500%5Cleft%281%2B%5Cfrac%7B4%7D%7B100%7D%5Cright%29%5E%7B1%7D)
![\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7BA%3D%5Cfrac%7B3500%20%5Ctimes%20104%7D%7B100%7D%7D%20%5C%5C%5C%5C%20%7BA%3D35%20%5Ctimes%20104%7D%20%5C%5C%5C%5C%20%7BA%3D3640%7D%5Cend%7Barray%7D)
Hence amount owed at the end of 1 year is 3640
Alrighty Daniel I think I've figured it out for you. A and B are 55° each, and then C is 70°. Hope I've helped!!
Answer:
option 3
Step-by-step explanation:
Answer:
everyone got 6 pieces
Step-by-step explanation:
do you actually need a explanation?
Hi there,
Sol:
Length of the swimming pool = 260 m
Breadth of the swimming pool = 140 m
Let the height of the water in the swimming pool after pouring water be h meters.
Volume of the water poured = 54600 m3
l x b x h = 54600
260 x 140 x h = 54600
h = (54600) / (260 x 140)
h = 1.5 m = 150 cm
Hope it helps