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juin [17]
3 years ago
15

A train leaves at 15.42 and arrives at its destination at 16.56.

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

284.2 KM/HR

Step-by-step explanation:

   16:56

   -15:42=1:24

S=D/T

S=103 km/ 7/5 hr

S=284.2 KM/HR

Tasya [4]3 years ago
5 0

Answer:

90/1.5=60 mph

Step-by-step explanation:

I assume that the train is traveling at constant speed.

Between 12:45 pm and 2:15 pm the train has traveled 180-90=90 miles. So 90 miles in 1.5 hours which means that its speed is 90/1.5=60 mph

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Answer:

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right )

We rearrange the fractions as improper  fractions for easier division as follows;

2\dfrac{1}{3}  = \dfrac{7}{3}

-3\dfrac{2}{3} = -\dfrac{11}{3}

Therefore, we have;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

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2 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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