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juin [17]
3 years ago
15

A train leaves at 15.42 and arrives at its destination at 16.56.

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

284.2 KM/HR

Step-by-step explanation:

   16:56

   -15:42=1:24

S=D/T

S=103 km/ 7/5 hr

S=284.2 KM/HR

Tasya [4]3 years ago
5 0

Answer:

90/1.5=60 mph

Step-by-step explanation:

I assume that the train is traveling at constant speed.

Between 12:45 pm and 2:15 pm the train has traveled 180-90=90 miles. So 90 miles in 1.5 hours which means that its speed is 90/1.5=60 mph

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Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
3 years ago
Math help owo pls will reword #_# pleath
timama [110]

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lorasvet [3.4K]

Answer:

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Step-by-step explanation:

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(8/9)×9 ×x = 32×9

8x = 32×9

Divide through by 8

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6 0
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Ilya [14]

Hey!

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Soloha48 [4]

(x-4)^2-11

How?

\\ \sf\longmapsto (x-4)^2-11

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Verified

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