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PilotLPTM [1.2K]
1 year ago
5

How do I solve this? I know it's easy but I don't understand clearly​

Mathematics
1 answer:
faltersainse [42]1 year ago
8 0

The answer is r = p/2n - x/n

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What type of relationship does this graph show?
makvit [3.9K]

Answer:

inverse relationship

Step-by-step explanation:

This is inverse becuase as masss increases acceleration decreaes

If this answer was correct plz consider marking brainlist

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3 years ago
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If a triangle has a height of 12 in and a base of 5 inbwhats the area
Yuliya22 [10]
Area of a triangle
A=h x b/2=12 x 5/2=30
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Write an equation in point-slope form for the line that passes through the point with the given slope. point: (4,2) and m=3
jonny [76]

Answer:

y = 3x - 10

Step-by-step explanation:

4 0
3 years ago
Which graph represents <br> y= -2x?
Kamila [148]
It would be the second graph since the coefficient is negative
5 0
3 years ago
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The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

* if x>1, then x-1>0.

* Also since the parabola opens up, then y>5.

So let's solve y=(x-1)^2+5 for x.

Subtract 5 on both sides:

y-5=(x-1)^2

Take square root of both sides:

Plus/minus sqrt(y-5)=x-1

We want x-1>0:

Sqrt(y-5)=x-1

Add 1 on both sides:

Sqrt(y-5)+1=x

Swap x and y:

Sqrt(x-5)+1=y

x>5

y>1

3 0
3 years ago
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