Answer:
(0, - 3) and (4, 5)
Step-by-step explanation:
Given the 2 equations
y = x² - 2x - 3 → (1)
y = 2x - 3 → (2)
Substitute y = x² - 2x - 3 into (2)
x² - 2x - 3 = 2x - 3 ← subtract 2x - 3 from both sides
x² - 4x = 0 ← in standard form
x(x - 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x = 0
x - 4 = 0 ⇒ x = 4
Substitute these values into (2) for corresponding values of y
x = 0 → y = 2(0) - 3 = 0 - 3 = - 3 ⇒ (0, - 3 )
x = 4 → y = 2(4) - 3 = 8 - 3 = 5 ⇒ (4, 5 )
