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Lelu [443]
4 years ago
8

Solve y=x2-2x-3 Y=2x-3

Mathematics
1 answer:
MrRa [10]4 years ago
4 0

Answer:

(0, - 3) and (4, 5)

Step-by-step explanation:

Given the 2 equations

y = x² - 2x - 3 → (1)

y = 2x - 3 → (2)

Substitute y = x² - 2x - 3 into (2)

x² - 2x - 3 = 2x - 3 ← subtract 2x - 3 from both sides

x² - 4x = 0 ← in standard form

x(x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x = 0

x - 4 = 0 ⇒ x = 4

Substitute these values into (2) for corresponding values of y

x = 0 → y = 2(0) - 3 = 0 - 3 = - 3 ⇒ (0, - 3 )

x = 4 → y = 2(4) - 3 = 8 - 3 = 5 ⇒ (4, 5 )

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3 years ago
How many subsets of {1, 2, 3, 4, 6, 8, 10, 15} are there for which the sum of the elements is 15?
stepladder [879]

Answer:

512

Step-by-step explanation:

Suppose we ask how many subsets of {1,2,3,4,5} add up to a number ≥8. The crucial idea is that we partition the set into two parts; these two parts are called complements of each other. Obviously, the sum of the two parts must add up to 15. Exactly one of those parts is therefore ≥8. There must be at least one such part, because of the pigeonhole principle (specifically, two 7's are sufficient only to add up to 14). And if one part has sum ≥8, the other part—its complement—must have sum ≤15−8=7

.

For instance, if I divide the set into parts {1,2,4}

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Once one makes that observation, the rest of the proof is straightforward. There are 25=32

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natta225 [31]
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4 years ago
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USPshnik [31]

Answer:

Step-by-step explanation:

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