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3 years ago

Please help me!!! :(

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

4 0

Answer:

$15.75x^{10}y^{19}$

Step-by-step explanation:

To find the 5th term in the expansion, we first will need to apply the binomial theorem. I have attached an image of the binomial theorem formula due to not being able to type it.

After applying the binomial theorem and simplifying, you should get:

$512x^{18}y^{27}-576x^{16}y^{25}+288x^{14}y^{23}-84x^{12}y^{21}+\frac{63x^{10}y^{19}}{4}-\frac{63x^8y^{17}}{32}+\frac{21x^6y^{15}}{128}-\frac{9x^4y^{13}}{1024}+\frac{9x^2y^{11}}{32768}-\frac{y^9}{262144}$

Our 5th term here is: $\frac{63x^{10}y^{19}}{4}$ which is equal to $15.75x^{10}y^{19}$

~Hope this helps! Sorry if my answer is confusing at all, it's pretty difficult to explain.~

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If f(x) = x and g(x) = 2, what is (f•g)(x)?

tamaranim1 [39]

Answer:

Step-by-step explanation:

(f*g)(x)=(2)*(x)=2x

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3 years ago

(+25 points!) Completeing the square.... Please help meee:)

katen-ka-za [31]

Answer:

$\large \boxed{\sf \ \ 3 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

$3x^2+3y^2+12x-9y+12=0\\\\\text{*** divide by 3 both sides***}\\\\x^2+y^2+4x-3y+4=0\\\\\text{*** Let's notice that: ***}\\\\*** \ x^2+4x=(x+2)^2-2^2=(x+2)^2-4 \ \ and \\\\*** \ y^2-3y=(y-\dfrac{3}{2})^2-\dfrac{3^2}{2^2}=(y-\dfrac{3}{2})^2-\dfrac{9}{4}\\\\\text{ *** complete the two squares ***}\\\\x^2+y^2+4x-3y+4=(x+2)^2-4+(y-\dfrac{3}{2})^2-\dfrac{9}{4}+4=0$

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So, the radius of the circle is...

$\sqrt{\dfrac{9}{4}}=\dfrac{3}{2}$

..and the diameter is two times the radius, so this is is

$\large \boxed{\sf \ \ 3 \ \ }$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0

3 years ago

If I'm adding mixed numbers so the fractional part is less than 1. How would I solve 9 5/10 + 6 3/10?

Crank

The answer would be 15 4/5. This is because 9 + 6 is 15, and 5/10 + 3/10 is 8/10. We can add these two fractions together because they have the same denominator. So it would be 15 8/10, and 8/10 simplified would be 4/5(because i divided 8 and 10 by the same number until they can't be divided by a whole number anymore). So the answer would be 15 4/5, I hope this helped :)

8 0

3 years ago

The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza do

xz_007 [3.2K]

Answer:

The minimum width of the placemat is 10 inches.

Step-by-step explanation:

Let suppose that placemat has a square form, whose width must be at least equal to the diameter of the pizza, so that pizza does not touch the table. Hence, the following relationship is obtained:

$w = D$

Where:

$w$ - Width of the placemat, measured in inches.

$D$ - Diameter of pizza, measured in inches.

The area of the pizza, measured in square inches, is determined by this formula:

$A = \frac{\pi}{4} \cdot D^{2}$

The diameter is cleared afterwards:

$D = \sqrt{\frac{4\cdot A}{\pi} }$

If $A = 78.5\,in^{2}$ and $\pi = 3.14$ , then:

$D = \sqrt{\frac{4\cdot (78.5\,in^{2})}{3.14} }$

$D = 10\,in$

The minimum width of the placemat is 10 inches.

4 0

4 years ago

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PLEASE HELP 20 POINTS

shepuryov [24]

Period would be the distance between 2 peaks

looking at the graph there is a peak on x= 1 and then a peak on x= 4
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the amplitude is the midpoint between the highest point and lowest point
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the high point is y=1 and the low point is y = -2
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the answer is the first one.

6 0

4 years ago

Read 2 more answers