In a survey 230 people were asked their favorite color and 20% of the people surveyed choose blue. How many people choose blue?

There are 26 prize tickets in a bowl,labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen,not

labwork [276]

Answer:

3.1%, dependent event

Step-by-step explanation:

We have that vowel are 5, it is from A, E, I, O, U therefore the probability of drawing a vowel is:

5/26

since there are a total of 26 options to choose from. Then, when selecting that, we are left with 25 options and 4 vowels, therefore the probability would be:

4/25

Therefore the final probability is:

5/26 * (4/25) = 0.031

In other words, selecting a vowel and then another (without replacement) the probability is 3.1%

The events are dependent, since the first event affects the second event, since the number of vowels and the number of total options are reduced.

5 0

3 years ago

The regular price of a sweater is $ 42.99. It is on sale for 29% off. Find the sale price?

Feliz [49]

The sale price is $30.52
:)

3 0

3 years ago

That up there please heeeeelp

Tomtit [17]

Answer:

A(2)

Step-by-step explanation:

3 0

3 years ago

At the end of the last quarter, the Monkey Tail were losing by 20 points. The score was 54-34. Each basket is worth 2 points. If

spin [16.1K]

The answer is C. They need 10 more baskets to win the game.

3 0

3 years ago

Suppose that 37% of college students own cats. If you were to ask random college students if they own a cat what would the proba

Likurg_2 [28]

Using the binomial distribution, the probabilities are given as follows:

a) 0.37 = 37%.

b) 0.5065 = 50.65%.

c) 0.3260 = 32.60%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, the fixed parameter is:

p = 0.37.

Item a:

The probability is P(X = 1) when n = 1, hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{1,1}.(0.37)^{1}.(0.63)^{0} = 0.37$

Item b:

The probability is P(X = 3) when n = 3, hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.37)^{3}.(0.63)^{0} = 0.5065$

Item c:

The probability is P(X = 2) when n = 4, hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.37)^{2}.(0.63)^{2} = 0.3260$

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0

2 years ago